Electric fields and potential SLAPE

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Arizona State University *

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113

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Physics

Date

Dec 6, 2023

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pdf

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Uploaded by CorporalJellyfishMaster647

1 (1 point) Title of the Experiment: Electric Fields & Potential Student’s name: Karlie Slape Section SLN: PHY 114online TA’s Name: Yeshwanth Sangishetty Date of the experiment: 10/29/23

2 Objective: (3 points) The objective of this experiment is to understand and apply the concepts of electric fields and electric potential. We will be calculating the magnitude and direction of forces and defining equipotential lines. Experimental Data (3 points): Part 1: Table 1: (As indicated in the list of parameters on Canvas-Module 2) Distance from charge r (units) Point charge q (units) 0.85 meters +2 nanoCoulombs Table 2: E p1 E p2 E p3 E p4 E average 8.92V/m 9.08 V/m 8.92 V/m 9.40 V/m 9.08 V/m Part 2: Table 3: Ball charge (units) Deflection angle (units) Ball mass (units) Plate separation distance (units) 6.168e-9C 13degrees 0.05grams 20cm

3 Data Analysis (10 points): Be sure to include equations! Part 1: Calculate the electric field at one of the points in your configuration. E=k*q/r^2 q= 10^-9 C r=1m k= 8.99*10^9N *m^2/C^2 E= (9.08*10^9)*10^-9/1^2 = 9.08 Calculate the percent discrepancy between the above value and your average E. (Ecalc-Eave/Ecalc)*100= % (9.08-9.08/9.08)*100= 0% Part 2: Draw a free-body diagram of the pith ball. Using newton’s second law, calculate the electric field between the two plates. Eq=m*g tan(13) Q=6*10^-9C M=.00005kg Q=9.81m/s^2 E=DeltaV/DeltaR DelV= E*DelR DelR=0.23m 0.00005*9.81*tan(13) 6*10^-9 = 18873.5V/m Using this field, calculate the potential difference between the two plates. V= E*d

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4 Results (3 points) Table 4: E average (units) E calc (units) Percent discrepency 9.08V/m 9.08V/m 0% Table 5: E between plates ( units) Potential difference ( units ) 18873.5V/m Post Lab Questions (5 points): 1. When experimentally comparing E field at different distances, do you find the relation that you expect? The relation when comparing different distances will be different. This was expected. 2. You performed part 1 with a positive test charge. What would change with a negative test charge? If the test was performed with a negative charge, the results would be inverse. It would be the opposite direction. 3. In part 2, why does your pith ball travel against the direction of the electric field? Because the ball has a positive charge, it moves against the direction of field. 4. After rubbing on the apparaTapus, your pith pall became negatively charged. What type of charge does the apparaTapus now have? The apparatus has a positive charge. 5. If you have a positive and negative charge nearby one another, which direction would the field between them point? The direction would be moving from positive to negative. Discussion and Conclusion (5 points): The purpose of the experiment was to understand and apply the concepts of electric fields and electric potential as well as calculate the magnitude and direction of forces and defining equipotential lines. The first experiment yielded a 0% discrepancy, both E(ave) & E(calc) were 9.08V/m. A possible source of error would be misreading the values on the website for the field or misplacing the points.

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