Electric fields and potential SLAPE
.pdf
keyboard_arrow_up
School
Arizona State University *
*We aren’t endorsed by this school
Course
113
Subject
Physics
Date
Dec 6, 2023
Type
Pages
4
Uploaded by CorporalJellyfishMaster647
1
(1 point)
Title of the Experiment: Electric Fields & Potential
Student’s name:
Karlie Slape
Section SLN: PHY 114online
TA’s Name:
Yeshwanth Sangishetty
Date of the experiment: 10/29/23
2
Objective: (3 points)
The objective of this experiment is to understand and apply the concepts of electric fields
and electric potential. We will be calculating the magnitude and direction of forces and
defining equipotential lines.
Experimental Data (3 points):
Part 1:
Table 1: (As indicated in the list of parameters on Canvas-Module 2)
Distance from charge r (units)
Point charge q (units)
0.85 meters
+2 nanoCoulombs
Table 2:
E
p1
E
p2
E
p3
E
p4
E
average
8.92V/m
9.08 V/m
8.92 V/m
9.40 V/m
9.08 V/m
Part 2:
Table 3:
Ball charge (units)
Deflection angle (units)
Ball mass (units)
Plate separation distance (units)
6.168e-9C
13degrees
0.05grams
20cm
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
Path of trajectory
AV
An electron is fired at a speed vj = 4.7 x 106 m/s and at an
angle 0; = 37.1° between two parallel conducting plates as
shown in the figure. If s = 2 mm and the voltage difference
between the plates is AV = 99.6 V, determine how close, w,
the electron will get to the bottom plate. Put your answer
in meters and include at 6 decimal places in your answer.
Do not include units. The x-axis of the coordinate
system is in the middle of the parallel plate capacitor.
arrow_forward
A proton (m = 1.67 x 10-27 kg) travels a distance of 3.2 cm
parallel to a uniform electric field 3.4 x105 V/m between
the plates shown in the figure. If the initial velocity is 1.5 x
105 m/s, find the magnitude of its final velocity in m/s. (*
Ignore gravity)
Round your answer to 0 decimal places.
arrow_forward
If a Helium nucleus moves in the direction of an electric field generated by a
stationary positive source charge, …
a) the course of action is non-spontaneous; work is required.
b) the strength of electric field is increasing from the source charge.
c) the force acting on the Helium nucleus is increasing.
d) the electric potential energy is decreasing.
10. Particle 1 and Particle 2 emerge into a mass spectrograph emerge with identical
velocity. If the radius of curvature of particle 1 is larger than the radius of
curvature for particle 2, then …
a) particle 1 is of greater mass than particle 2
b) particle 1 has a smaller charge than particle 2
c) particle 1 has a larger mass/charge ratio than particle 2
d) particle 1 has a larger charge/mass ratio than particle 2
e) nothing can be concluded.
arrow_forward
1- Firstly, the electrons produced by heating a tungsten filament are accelerated by a potential difference ΔV. Knowing that the electrons are initially at rest, use the principle of conservation of energy to express the final speed of the electrons (v), as a function of their mass (m), their charge (e) and the potential difference (ΔV) to which they are exposed.2- Using the relationship obtained in step 1, give an expression for the non-relativistic momentum of the electrons.3- Pose the de Broglie relation which allows us to obtain the wavelength for the electron. Then express this wavelength using the relationship obtained in step 2 and Planck's constant.4- The accelerated electrons will strike the graphite film (see image). Express the path difference between electrons 1 and 2 as a function of the angle θ and the distance between 2 planes of carbon atoms of graphite film (d).5- Use the constructive interference condition to obtain a relationship between the path difference (obtained…
arrow_forward
I need to answer of 6th question
arrow_forward
QUESTION 4
An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate.
The plates are separated by a distance of 1.39 cm, and the electric field within the capacitor has a magnitude of
1743307 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? (Give your answer in 2 d.p.
with scientific notation(i.e. 1.23e-12)}
1
Electric field
Electron
F
+ + + + + + + + + +
arrow_forward
Situation: A single electron accelerates between the cathode and the anode that has a potential difference of 2000 V. The charge of an electron is 1.6 x 10^-19C and its mass is 9.1 x 10^-31 kg.
2. Compute for the work done on the electron passing through a potential difference of2000 V. Give your answer in joules.3. Kinetic energy of the electron the work done on the electron. Write the formula for kinetic energy in terms of mass m and speed v.4. Using your answers in #2 and #3, find the speed of the electron.
arrow_forward
1 c)Write the answer correctly and dont copy from internet provide write information please
arrow_forward
Problem 2: Consider the parallel-plate capacitor shown in the figure. The plate separation
is 5.9 mm and the the electric field inside is 24 N/C. An electron is positioned halfway between the
plates and is given some initial velocity, v₁.
Randomized Variables
d = 5.9 mm
E = 24 N/C
+ + + + + + + +
d
Otheexpertta.com
Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate?
Part (b) If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. What will its
speed be, in meters per second, when it reaches the positive plate in this case?
select part
Vf,b=1
arrow_forward
4. Consider an object of mass 52.7 kg Assume that it is made up of equal numbers of protons, neutrons, and electrons. and you initially put the boxes of protons and electrons 62 m apart. Now you want to take the two boxes and move them farther apart, to a new distance of 117 m apart. How much work (that is, energy) would you have to expend to pull the boxes that much farther apart, fighting against the electrostatic attraction between them?
1.74E+27 J
2.17E+26 J
4.34E+26 J
8.68E+26 J
arrow_forward
File
2
Undo
A2
22
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
Home Insert
A
B
1 Charge (C)
Magnitue (N)
2
0.02
449.378
3
0.028
229.274
4
0.036
138.677
0.044
92.847
0.052
66.476
0.06
49.931
0.068
38.873
0.076
31.12
0.084
25.475
0.092 21.237
0.1
17.975
22
Paste
XAY
Clipboard 5
V X✓
Sheet1
Page Layout
Calibri
B I U-
C
0.02
D
Force magnitude (N)
Formulas Data Review View
Font
500
450
400
350
300
250
200
150
100
50
0
0
11 - AA
a
A
V
E
F
0.02
5
229.274
G
138.677
92.847
0.04
Help
Series1
44995ce magnitude (N) vs Distance(m)
M
Alignment
H
→=
y=0.1798x2
R² = 1
0.06
Distance (m)
General
0.08
$ % 98
Power (Series1)
66.47649.9338.87331.1225.47221.2377.975
J
Number
0.1
K
0.12
5
arrow_forward
=
2. In an electrode system potential equation is given as V(x, y)
x
are; for x =0.5 cm, y=1 cm V = V₁ =40 kV and x =1 cm, y=1cm V = V₂ =0 V.
a) Determine the constant A and B.
b) Evaluate electric field equation. Determine maximum and minimum electric field strength values.
A
+ By and the boundary conditions
arrow_forward
1. How long does it take an electron to move from a cathode to a phosphorus TV screen 30 cm away,
under an applied voltage of 15kV? What is the final velocity, momentum, and kinetic energy? Sketch
the potential energy (in eV) as seen by the electron between the cathode and screen. Assume the screen
is grounded. Plot curves for the Kinetic Energy and Total Energy-sketching by hand! Demonstrate
how one can calculate the Force on the electron from your sketch. Did you label your axes on all
graphs?
arrow_forward
Please fill in the blanks. Suppose an electron (q equals negative e equals negative 1.6 cross times 10 to the power of negative 19 end exponent space text C end text space,m equals 9.1 cross times 10 to the power of negative 31 end exponent space text kg end text) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.
arrow_forward
An electron is fired at a speed v, = 4.2 x 105 m/s and at an angle 6 = 37° between two parallel conducting plates as shown in the
figure. If s = 1.8 mm and the voltage difference between the plates is AV = 99.6 V, determine how close, w, the electron will get to the
bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the
coordinate system is in the middle of the parallel plate capacitor.
arrow_forward
The distance, r, between the proton and electron in the hydrogen atom is about 10-10 m. Determine the value of the kinetic energy of the electron. Provide your answer in electron-volts (eV).
arrow_forward
Two large parallel plates are placed horizontally with respect to each other and are then connected to a 100-V battery. If the distance between the plates is 1 cm, the uniform electric field between the plates is 104 N/C in the upward direction as shown by the vectors in the figure. If the electron is released from rest at the upper plate, calculate:
1. kinetic energy of the electron after traveling 1cm to the lower plate
2. the time required for it to travel this distance
arrow_forward
Please give a clear explanation
arrow_forward
The van de Graaff generator
- our generator makes 400,000 volts. you can easily use it to create Sparks in the air there since it takes around 33,000 volts to make a spark that's 1 cm long. in general double the length takes double the voltage
The data
distance , number of spackes per 30 seconds
10cm , 2
9cm , 20
8cm , 30
7cm , 46
The question: determine a way to estimate the number of Sparks per second for several different distances between the two orbs and make a graph depicting this relationship
arrow_forward
In an experiment replicating Millikan’s oil drop experiment, apair of parallel plates are placed 0.0200 m apart and the top plate is positive.When the potential difference across the plates is 240.0 V, an oil drop of mass2.0 × 10-11 kg gets suspended between the plates. (e = 1.6 × 10-19 C)a. Draw a free body diagram to describe the situation.b. What is the charge on the oil drop?c. Is there an excess or deficit of electrons on the oil drop? How many electrons are in excess or deficit?
arrow_forward
1
arrow_forward
1. Find E at (0, 0, 5) m due to Q1 = 0.35 µ C at (0, 4, 0) m and Q2 = -0.55 µ C at
(3, 0, 0) m (see the figure).
E,E,
7.
R,
R,
of
(0, 4, 0)
(3,0, 0)
arrow_forward
PROBLEMS
Q1: An electron starts from rest at the negative plate separated
by 2 cm and having a potential difference of 1500 volts. How
long does it take to reach a speed of 10' m/s and what position
does it reach at this speed? Find the kinetic energy of the
electron when it hits the anode?
(Ans;0.38cm,
1500eV)
arrow_forward
1. Let E = 400ảy – 300đy + 500ả, in the neighborhood of point P(6,2,-3). Find
the incremental work done in moving a 5C charge a distance of 1mm in
the direction specified by:
a. dx + ảy + đ,
b. — 2ӑx + Зау — ӑ,
2. If E = -xảx + yã, V/m, find the work involved in moving a unit positive
charge on a circular arc, the circle at the origin, from x = a to x = y =
a/V2.
3. Let V = 6xy²z3 + 5 In(x2 + y2 + 3z2)V in free space. Evaluate each of the
following quantities at P(2,3, -1), find:
а. V
b. Е
c. |JE||
d. D
e. ||D||
f. ån
arrow_forward
The acceleration voltage of an Electron Gun is Va = 500 V and the distance between Kathode and Anode is d = 5cm. Non-relativistic calculation can be used.
Calculate how fast the electrons are moving when they pass the anode.
Find the work done by the electric field on an electron.
What time does the electron take to get from the hot cathode to the anode?
Now the acceleration voltage changes and electrons are passing the anode with a speed of v=2,054⋅107ms. Find the acceleration voltage.
arrow_forward
Calculate the speed of an electron (in m/s) after it accelerates from rest through a potential
difference of 280 V.
m/s
Submit Answer
Tries 0/2
arrow_forward
6. Solve for the Electric flux of a sphere if the radius r of the sphere is 10.57 nm and its
charge q is 6.11 nC
7. Find the electric potential of a charge q with 491 nC and distance of 200 cm
8. What Fuse should be used if the appliance has 240 V and 1600 W?
9. Find the distance of two charges with q1 = 94 nC and q2 = 45 µC, the force of the 2
charges is 0.81 N
10. Find the Voltage of a circuit if the value of resistance is 33 n2 and current of 18 µA
11. Find the Electric flux Pg if the Electric Field E with a value of 5.78 µC is contained
in a conical container with a radius of 1.8 m and a height of 4.56 m
12. Find the resistance of a circuit runs with 190 µA and 122 nV
13. Find the Value of the point charge qo if it has a voltage of 5.13 V and electric
potential energy of 4.35 x 10-5
14. Find the Charge of a point charge q if its Electric Field E has 12.1 N/C and a distance
of 1,8 m
15.-18.5 What is the (A) total charge (Qtotal) and the charge on each capacitor of
the given series…
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Related Questions
- Path of trajectory AV An electron is fired at a speed vj = 4.7 x 106 m/s and at an angle 0; = 37.1° between two parallel conducting plates as shown in the figure. If s = 2 mm and the voltage difference between the plates is AV = 99.6 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor.arrow_forwardA proton (m = 1.67 x 10-27 kg) travels a distance of 3.2 cm parallel to a uniform electric field 3.4 x105 V/m between the plates shown in the figure. If the initial velocity is 1.5 x 105 m/s, find the magnitude of its final velocity in m/s. (* Ignore gravity) Round your answer to 0 decimal places.arrow_forwardIf a Helium nucleus moves in the direction of an electric field generated by a stationary positive source charge, … a) the course of action is non-spontaneous; work is required. b) the strength of electric field is increasing from the source charge. c) the force acting on the Helium nucleus is increasing. d) the electric potential energy is decreasing. 10. Particle 1 and Particle 2 emerge into a mass spectrograph emerge with identical velocity. If the radius of curvature of particle 1 is larger than the radius of curvature for particle 2, then … a) particle 1 is of greater mass than particle 2 b) particle 1 has a smaller charge than particle 2 c) particle 1 has a larger mass/charge ratio than particle 2 d) particle 1 has a larger charge/mass ratio than particle 2 e) nothing can be concluded.arrow_forward
- 1- Firstly, the electrons produced by heating a tungsten filament are accelerated by a potential difference ΔV. Knowing that the electrons are initially at rest, use the principle of conservation of energy to express the final speed of the electrons (v), as a function of their mass (m), their charge (e) and the potential difference (ΔV) to which they are exposed.2- Using the relationship obtained in step 1, give an expression for the non-relativistic momentum of the electrons.3- Pose the de Broglie relation which allows us to obtain the wavelength for the electron. Then express this wavelength using the relationship obtained in step 2 and Planck's constant.4- The accelerated electrons will strike the graphite film (see image). Express the path difference between electrons 1 and 2 as a function of the angle θ and the distance between 2 planes of carbon atoms of graphite film (d).5- Use the constructive interference condition to obtain a relationship between the path difference (obtained…arrow_forwardI need to answer of 6th questionarrow_forwardQUESTION 4 An electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate. The plates are separated by a distance of 1.39 cm, and the electric field within the capacitor has a magnitude of 1743307 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? (Give your answer in 2 d.p. with scientific notation(i.e. 1.23e-12)} 1 Electric field Electron F + + + + + + + + + +arrow_forward
- Situation: A single electron accelerates between the cathode and the anode that has a potential difference of 2000 V. The charge of an electron is 1.6 x 10^-19C and its mass is 9.1 x 10^-31 kg. 2. Compute for the work done on the electron passing through a potential difference of2000 V. Give your answer in joules.3. Kinetic energy of the electron the work done on the electron. Write the formula for kinetic energy in terms of mass m and speed v.4. Using your answers in #2 and #3, find the speed of the electron.arrow_forward1 c)Write the answer correctly and dont copy from internet provide write information pleasearrow_forwardProblem 2: Consider the parallel-plate capacitor shown in the figure. The plate separation is 5.9 mm and the the electric field inside is 24 N/C. An electron is positioned halfway between the plates and is given some initial velocity, v₁. Randomized Variables d = 5.9 mm E = 24 N/C + + + + + + + + d Otheexpertta.com Part (a) What speed, in meters per second, must the electron have in order to make it to the negatively charged plate? Part (b) If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. What will its speed be, in meters per second, when it reaches the positive plate in this case? select part Vf,b=1arrow_forward
- 4. Consider an object of mass 52.7 kg Assume that it is made up of equal numbers of protons, neutrons, and electrons. and you initially put the boxes of protons and electrons 62 m apart. Now you want to take the two boxes and move them farther apart, to a new distance of 117 m apart. How much work (that is, energy) would you have to expend to pull the boxes that much farther apart, fighting against the electrostatic attraction between them? 1.74E+27 J 2.17E+26 J 4.34E+26 J 8.68E+26 Jarrow_forwardFile 2 Undo A2 22 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 Home Insert A B 1 Charge (C) Magnitue (N) 2 0.02 449.378 3 0.028 229.274 4 0.036 138.677 0.044 92.847 0.052 66.476 0.06 49.931 0.068 38.873 0.076 31.12 0.084 25.475 0.092 21.237 0.1 17.975 22 Paste XAY Clipboard 5 V X✓ Sheet1 Page Layout Calibri B I U- C 0.02 D Force magnitude (N) Formulas Data Review View Font 500 450 400 350 300 250 200 150 100 50 0 0 11 - AA a A V E F 0.02 5 229.274 G 138.677 92.847 0.04 Help Series1 44995ce magnitude (N) vs Distance(m) M Alignment H →= y=0.1798x2 R² = 1 0.06 Distance (m) General 0.08 $ % 98 Power (Series1) 66.47649.9338.87331.1225.47221.2377.975 J Number 0.1 K 0.12 5arrow_forward= 2. In an electrode system potential equation is given as V(x, y) x are; for x =0.5 cm, y=1 cm V = V₁ =40 kV and x =1 cm, y=1cm V = V₂ =0 V. a) Determine the constant A and B. b) Evaluate electric field equation. Determine maximum and minimum electric field strength values. A + By and the boundary conditionsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegePrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning