6-1 lab report

PHY 101L Module Six Lab Report Name: Zachary Prat Date: 10/3/2023 Activity 1: Elastic Collision with Equal Masses Table 1A: Cart A Before Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A 0.0668 kg .35 m .35 s .316 1.10 m/s .29 s .31 s Table 1B: Cart A After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A ’ 0.0668 0.01 .29 .263 0.03 m/s .25 .25 Table 1C: Cart B After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v B ’ 0.07 .5 m .34 s .333 1.50 m/s .32 s .34 s Calculations for Activity 1: Elastic Collision with Equal Masses ? ? ? ? + ? ? ? ? = ? ? ? ? + ′ ? ? ? ? ′ Percent difference = | first value − second value first value + second value 2 | x 100% 1. Calculate the momentum of the system before the collision (the left side of the equation) and after the collision (the right side of the equation). .0668 * 1.10 + .070 * 0 = 0.073 .0668 * 1.10 + .070 * 1.50 = 0.073 + .105 = 0.178

2. Calculate the percent difference between the two values. 0.073 - 0.178 = -0.105 0.073 + .178 = 0.251 -0.105/0.251/2 -20.9 % 3. Explain any difference in the values before and after the collision. The loss comes from energy being conserved at the point of collision between the carts. Activity 2: Elastic Collision: Mass Added to Cart A Table 2A: Cart A Before Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A 0.1915 kg .5 m .64 s .62 .806 m/s .63 s .59 s Table 2B: Cart A After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v A ’ 0.1915 kg .2 m .40 s .39 .51 m/s .37 s .40 s Table 2C : Cart B After Collision Cart A mass, m (kg) Distance, d (m) Time, t (s) Average time, t (s) Velocity = d / t (m/s) v B ’ .07 kg .5 m .22 s 0.236 2.18 m/s .25 s .24 s Calculations for Activity 2: Elastic Collision: Mass Added to Cart A Helpful equations : Momentum before the collision = ? ? ? ? + ? ? ? ? Momentum after the collision = ? ? ? ? + ′ ? ? ? ? ′ ? ? ? ? + ? ? ? ? = ? ? ? ? + ′ ? ? ? ? ′ Percent difference = | first value − second value first value + second value 2 | × 100% 1. Calculate the momentum of the system before the collision (the left side of the equation) and after the collision (the right side of the equation). .1915 * (.806) + .07 * (0) = 0.154