phys 2 lab 4

Capacitors Aaron Besa Lab Due: June 21, 2023 Prof. Shylnov Physics 221-L01 TA: Alireza Alipour Raw Data type Capacitance (nF) blue 7.6 orange 16.7 disk 22.3 Capacitance in series = 4.23 ( 1 7.6 + 1 16.7 + 1 22.3 ) −1 Exp: 4.7 Capacitance in parallel 7.6+16.7+22.3 = 46.6 Exp: 35.6 1. Calculate the capacitance using Equation 1 for the various separation distances of task 1 (for part 2a). How do these values compare with the data taken with the capacimeter? Don’t forget to take into account the dielectric constant for air. Using equation 1: distance (m) exp capacitance (F) calculated capacitance 0.01 9.50E-11 (1.0054)* = 2.78E-11 8.85𝐸−11(.1 2 )π .01 0.03 7.38E-11 9.27E-12 0.05 7.00E-11 5.56E-12 0.07 6.80E-11 3.97E-12 0.09 6.69E-11 3.09E-12 0.12 6.57E-11 2.32E-12 The calculated capacitance is slightly smaller than the experimental capacitance and this could be due to the experimental errors such as environment or measurement error with distancing of the plates.

2. Calculate the dielectric constant for the paper used. How do your values compare with the listed value from the table above? 1 white sheet 10 white sheets 𝐶 = 𝑘 ϵ 0 𝐴 𝑑 𝑘 = 𝑑𝐶 ϵ 0 𝐴 𝑘 = (.01)(8.76*10 −11 ) (8.85*10 −12 )(π(.1 2 ) = 3. 15 𝐶 = 𝑘 ϵ 0 𝐴 𝑑 𝑘 = 𝑑𝐶 ϵ 0 𝐴 𝑘 = (.01)(9.18*10 −11 ) (8.85*10 −12 )(π(.1 2 ) = 3. 30 The dielectric constants are slightly larger than the given range of white paper. The data may be off because of experimental errors such as units of uncertainty of moving the plate. 3. Calculate the dielectric constant for the transparency sheets. Does the capacitance of the parallel plates depends on the thickness of the dielectric? 𝐶 = 𝑘 ϵ 0 𝐴 𝑑 𝑘 = 𝑑𝐶 ϵ 0 𝐴 𝑘 = (.01)(8.75*10 −11 ) (8.85*10 −12 )(π(.1 2 ) = 3. 14 Yes the thickness of the dielectric affects the capacitance of the parallel capacitors. We can see that from 1 sheet of paper to 10 sheets, the dielectric constant increased.