Projectile Motion Lab

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University of Waterloo *

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430

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Physics

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Jan 9, 2024

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Projectile Motion Lab Partner: Benny Huynh, Dennis Vo SPH4U Antonela Rusu Submitted by: Tommy Nguyen March 26 h , 2019 1
PURPOSE The purpose of this lab was to analyze the properties of downward projectile motion. This motion will show how the initial velocity and launch angle will impact the horizontal distance and the time. HYPOTHESIS The horizontal displacement and the time will not change since there is no change in initial velocity and launch angle. APPARATUS & METHOD PROCEDURE 2
1. The experiment was set up as shown above. dy and ∆h was recorded. 2. A metal ball was released at the top of the textbook. 3. When the ball fell off the textbook, a timer was started. 4. The ball fell onto carbon paper and the timer was stopped. 5. The distance from the edge of the desk to the mark left on the carbon paper was measured. 6. The horizontal distance and the time were recorded. 7. Repeated the experiment 10 times. OBSERVATIONS Trial d y (m) ∆h (m) d x (m) t (s) 1 0.949 0.0899 0.378 0.360 2 0.949 0.0899 0.375 0.330 3 0.949 0.0899 0.379 0.320 4 0.949 0.0899 0.373 0.340 5 0.949 0.0899 0.377 0.350 6 0.949 0.0899 0.375 0.330 7 0.949 0.0899 0.376 0.340 8 0.949 0.0899 0.378 0.370 9 0.949 0.0899 0.373 0.370 10 0.949 0.0899 0.377 0.340 Avarage d xav (m) d yav (m) ∆h av (m) t av (s) V x (m/s) v iy (m/s) V i (m/s) Length of the 3
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textbook (m) 0.376 0.949 0.0899 0.345 1.09 1.06 1.52 0.222 CALCULATIONS & MANIPULATIONS Experimental Initial Velocity Theoretical Initial Velocity 4 v i = v x 2 + v iy 2 v i = ( 1.09 m / s ) 2 + ( 1.06 m / s ) 2 v i = 1.52 m / s θ = tan 1 ( v iy v x ) θ = tan 1 ( 1.06 m / s 1.09 m / s ) θ =[ E 44.2 ° S ] The experimentalinitial velocity was 1.52 m / s [ E 44.2 ° S ] . v x ¿ θ v iy v i d x = v x ×t v x = d x t v x = 0.376 m 0.345 s v x = 1.09 m / s [ E ] d y = v iy t + 1 2 a y t 2 v iy = d y 1 2 a y t 2 t v iy = 0.949 m + 4.9 m / s 2 ( 0.345 s ) 2 0.345 s v iy = 1.06 m / s [ S ] θ = sin 1 ( ∆h l ) θ = sin 1 ( 0.0899 m 0.222 m ) θ =[ E 23.9 ° S ] ¿ θ l ∆h
v i = 10 7 g∆h v i = 10 7 ( 9.8 m / s 2 ) ( 0.0899 m ) v i = 1.12 m / s Percent Error for Initial Velocity %error = | experimental theoretical | theoretical × 100% %error = | 1.52 m / s 1.12 m / s | 1.12 m / s × 100% %error = 35.7 % Percent Error for Angle (θ) %error = | experimental theoretical | theoretical × 100% %error = | 44.2 ° 23.9 ° | 23.9 ° × 100% %error = 84.9% , 5
QUESTIONS 1. The vertical component of the initial launch velocity can be determined from the vertical displacement, time and the vertical acceleration. Using the equation d y = v iy t + 1 2 a y t 2 , the vertical component of the initial launch velocity was 1.06 m/s [D]. 2. The horizontal component of the initial launch velocity can be determined from the horizontal displacement, time and the horizontal acceleration. Since this is a horizontally launched projectile, there is no horizontal acceleration. Using this equation d x = v x ×t , the horizontal component of the initial launch velocity was 1.09 m/s [E]. 3. The experimental initial velocity was 1.52 m/s and the theoretical initial velocity was 1.12 m/s. The experimental and the theoretical value for initial velocities were not close. This difference caused a slight huge percent error of 35.7%. The launch angle was also very different as the experimental was 44.2 and the theoretical was 23.9 . This difference caused a percent error of 84.9%. 4. In order to find the final impact velocity, we need the horizontal velocity and the final vertical velocity. To find the final vertical velocity the equation bellow can be used. 6 v x ¿ θ v fy = v iy 2 + 2 a y d y v fy = ( 1.06 m / s ) 2 + 2 ( 9.8 m / s 2 ) ( 0.949 m ) v fy = 4.44 m / s [D] v f = v x 2 + v fy 2 v = ( 1.09 m / s ) 2 +( 4.44 m / s ) 2
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The finalimpact velocity of the metalball was 4.57 m / s [ E 76.2 ° S ] EXPERIMENTAL UNCERTAINTIES 1. The amount of trial performed error. If it was increased, the average measurements would be more reliable. 2. The main source of error is likely to be the effect of air resistance, which is very difficult to account for theoretically at this level. When the projectile experienced more air resistance, it would not allow the projectile to complete its full motion. It would be the horizontal acceleration impact the horizontal velocity and horizontal displacement. 3. The accuracy of measurements, the smallest unit which allow 7 v fy v f
to measure is millimeter. This would only allow us to be so precise in calculations. Another uncertainty is the accuracy of stopwatch, it only allowed to measure to a hundredth of a second which could affect the precision of the experimental calculations. CONCLUSION After finishing this lab, I conclude that one of my hypothesis is correct while my other one had some problems. “The horizontal displacement and the time will not change since there is no change in initial velocity and launch angle.” This turned out to be true since the horizontal displacement and the time was about the same each trial. Performing this lab helped me understand downward projectile motion and how a downward initial vertical velocity changes regular projectile motion. It has also helped me understand the relationship between complimentary angles, their horizontal displacement and times. By increasing the amount of trials completed, it would help better understand the importance of launch angle and initial velocity. 8