MATH303 Week 5 QUIZ 4 Attempt

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Sullivan University *

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302

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Statistics

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Apr 3, 2024

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The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate a 99% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer: ___239___ Hide question 1 feedback Z-Critical Value = NORM.SINV(.995) = 2.575 n = n = Question 2 0 / 1 point There is no prior information about the proportion of Americans who support gun control in 2018. If we want to estimate 92% confidence interval for the true proportion of Americans who support gun control in 2018 with a 0.2 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number) ___19___Incorrect Response( 20) Hide question 2 feedback Z-Critical Value =NORM.S.INV(.96) = 1.750686 n = n = Question 3 1 / 1 point
The population standard deviation for the height of college hockey players is 3.4 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 0.6 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer: ___ 87___ Hide question 3 feedback Z-Critical Value = NORM.SINV(.95) = 1.645 n = n = Question 4 0 / 1 point There is no prior information about the proportion of Americans who support free trade in 2018. If we want to estimate a 97.5% confidence interval for the true proportion of Americans who support free trade in 2018 with a 0.16 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number) ___46___Incorrect Response( 50) Hide question 4 feedback Z-Critical Value = NORM.S.INV(.9875) = 2.241403 n = n = Question 5 1 / 1 point
The population standard deviation for the height of college baseball players is 3.2 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer: ___ 57___ Hide question 5 feedback Z-Critical Value = NORM.S.INV(.95) = 1.645 n = n = Question 6 1 / 1 point The population standard deviation for the height of college basketball players is 3.4 inches. If we want to estimate 95% confidence interval for the population mean height of these players with a 0.5 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer: ___178___ Hide question 6 feedback Z-Critical Value = NORM.S.INV(.975) = 1.96 n = n = Question 7 1 / 1 point
There is no prior information about the proportion of Americans who support Medicare-for-all in 2019. If we want to estimate 95% confidence interval for the true proportion of Americans who support Medicare-for-all in 2019 with a 0.3 margin of error, how many randomly selected Americans must be surveyed? Answer: (Round up your answer to nearest whole number) ___11___ Hide question 7 feedback Z-Critical Value = NORM.S.INV(.975) = 1.96 n = n = Question 8 1 / 1 point A random sample found that forty percent of 100 Americans were satisfied with the gun control laws in 2017. Compute a 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017. Fill in the blanks appropriately. A 99% confidence interval for the true proportion of Americans who were satisfied with the gun control laws in 2017 is ( ___0.274___(50 %)___0.526___(50 %) ) (round to 3 decimal places) Hide question 8 feedback Z-Critical Value = NORM.S.INV(.995) = 2.575 LL = 0.4 - 2.575* UL = 0.4 -+2.575* Question 9 1 / 1 point
A recent study of 750 Internet users in Europe found that 35% of Internet users were women. What is the 95% confidence interval estimate for the true proportion of women in Europe who use the Internet? 0.309 to 0.391 0.305 to 0.395 0.321 to 0.379 0.316 to 0.384 Hide question 9 feedback Z-Critical Value = NORM.S.INV(.975) = 1.96 LL = 0.35 - 1.96* UL = 0.35 +1.96* Question 10 1 / 1 point Suppose a marketing company computed a 94% confidence interval for the true proportion of customers who click on ads on their smartphones to be (0.56 , 0.62). Select the correct answer to interpret this interval
There is a 94% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. 94% of customers click on ads on their smartphones. We are 94% confident that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. We are 94% confident that the true proportion of customers who click on ads on their smartphones is 0.59. Question 11 0.5 / 1 point Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was estimated that the current proportion of customers who click on ads on their smartphones is 0.42 based on a random sample of 100 customers. Compute a 92% confidence interval for the true proportion of customers who click on ads on their smartphones and fill in the blanks appropriately. ___ 0.334___(50 %) < p < ___0.507___Incorrect Response( 0.506, .506) (round to 3 decimal places) Hide question 11 feedback Z-Critical Value = NORM.S.INV(.96) = 1.750686 LL = 0.42 - 1.750686 * UL = 0.42 + 1.750686 *
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