M6 Exam

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Portage Learning *

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110

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Statistics

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Jan 9, 2024

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pdf

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M6: Exam - Requires Respondus LockDown Browser + Webcam Due No due date Points 50 Questions 5 Time Limit 90 Minutes Requires Respondus LockDown Browser Instructions You may only have the following items when taking an exam: computer, 1-2 pieces of blank scratch paper, a pen/pencil, and a calculator. You may ONLY use the equation sheets that are provided WITHIN the exam. The use of printed versions will be considered a violation of the Academic Integrity Policy. Attempt History Attempt Time Score LATEST Attempt 1 86 minutes 45 out of 50 Score for this quiz: 45 out of 50 Submitted Aug 28 at 6:09pm This attempt took 86 minutes. Question 1 10 /10 pts You may find the following files helpful throughout the exam: Statistics_Equation_Sheet = table.pdf)
A new drug is introduced that is supposed to reduce fevers. Tests are done with the drug. The drug is given to 60 people who have fevers. It is found that the mean time that it takes for the fever to get back to normal for this test group is 350 minutes with a standard deviation of 90 minutes. Find the 80% confidence interval for the mean time that the drug will take to reduce all fevers for all people. Answer the following questions: 1. Multiple choice: Which equation would you use to solve this problem? S S B ¥—fl——= < S X+t— va F Vn C - s N—n< < 7+ s |[N—n X Z=—— X+ 2= JndN=1 > F % JN=1 1_ D P+ z p(1-p) n 2. List the values you would insert into that equation. 3. State the final answer to the problem Your Answer: 1.A 2. n=60, s=90, |z = 350 3.
Table shows z=1.28 ~ {98 90 90 350 12878 < 1 <350 +1.28-% 335.13 < p < 364.87 The drug will ultimately sold to a very large number of people. So, we may assume a very large population. Since the sample size is greater than 30, we should use Case 1: Very large population and very large sample size. We are given the sample mean and sample standard deviation. So, we have n=60 x =350 s=90 We will use these values in the equation: _ s _ s A X—Z2— << x+Z2— Vn Vn For a 80% confidence level, we look at table 6.1 and find that z = 1.28. When we substitute these values into our equation, we get: 90 90 350 - 128 < u< 350+ 1.28 V60 V60 When we do the arithmetic on the right and left hand side, we get: 335.13 < < 364.87. Question 2 10/ 10 pts
You may find the following files helpful throughout the exam: Statistics_Equation_Sheet = (https://previous.nursingabc.com/upload/images/Help_file picture/Statistics Standard Normal Table & (https://previous.nursingabc.com/upload/images/Help_file picture/standardn T Table 5 (https://previous.nursingabc.com/upload/images/Help_file_picture/t- table.pdf) A certain school has 275 male students. The school nurse would like to know how many calories the male students consume per day. So, she samples 40 male students and finds that the mean calorie consumption of the 40 is 2670 calories per day with a standard deviation of 330 calories per day. Find the 95 % confidence interval for mean calorie intake of all the male students in the school. Answer the following questions: 1. Multiple choice: Which equation would you use to solve this problem? s B S A F—RreiCig& PR vn vn B X ts < '-I-ts X —t=—= < X n K Vn s N-—-n S N~—-n C. ¥—-z— < u< ¥x+z— Vi N - nJN-1 1_ D l,j:zp( p)
2. List the values you would insert into that equation. 3. State the final answer to the problem Your Answer: 1.C 2. N=275, n=40, s=330, |7 = 2670 3. For 95% confidence z=1.960 |267O 1.960-2% \/ 227755 410 < < 2670 + 1.960-35C \/ 227755__410 12575.3 < pu < 2764.7| The population is finite. So, we should use Case 3: Finite population. Use: In the statement of the problem, we are given: N=275 n=40 x =2670 s=330 For a 95% confidence level, table 6.1 gives z=1.96 e IR ol i R 2670 + 1.96 o i P a0 J275-1 O F P Va0 J 2751 2575.29 < u< 2764.71
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