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BIC472 Lab Report 2 PCR AGE Essay examples

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BIC472 Student Name: Darshan Trivedi

Partner’s Name: Manan

Assignment 2
POLYMERASE CHAIN REACTION
Total Marks: 12

1. (2 marks) In this experiment, you have amplified the D1S80 locus by PCR. Explain the advantages of using this locus to distinguish one person from another. Do you think you could use a coding gene for the same purpose? Clearly explain your answers.
D1S80 locus is placed on the short arm of the chromosome 1. This locus does not code for the arrangement for protein, yet it codes for a series of tandem repeats of 16 bp in human. Distinctive number of this allele has different number of repeats. These quantities of repeats are exceptional to every human. Primer …show more content…

Sr No.
Distance traveled by fragments in cm
Log molecular weight of each fragment
Molecular weight (bp)
1
11.7
2.7
501 bp
2
11.0
2.75
562 bp

Calculation:
Log molecular weight of the fragment of 1500 bp:=anti
Log (1500) = 3.18
Molecular weight of sample: (Genomic DNA Fragment # 2) = Antilog (2.75) = 562.
Number of repeats on Genomic DNA fragment #1: 113 bp + (n)(16 bp) + 32 bp = fragment size 113 bp + (n)(16 bp) + 32 bp = 501 bp (n)(16 bp) = 501 bp – 32 bp – 113 bp n = (356 bp / 16bp) n = 22.25 = 22 tandem repeats
The number of repeats on Genomic DNA fragment #1 is 22 Number of repeats on Genomic DNA fragment #2:
113 bp + (n)(16 bp) + 32 bp = fragment size 113 bp + (n)(16 bp) + 32 bp = 562 bp (n)(16 bp) = 562 bp – 32 bp – 113 bp n = (417 bp / 16bp) n = 26.06 = 26 tandem repeats
The number of repeats on Genomic DNA fragment #2 is 26
The number of repeat on Genomic DNA fragment #1 is 22 and on Genomic DNA fragment #2 is 26.
Genomic DNA is heterogenrous because it shows 2 fragments on 2% agarose gel which come from parents, mom and dad. Moreover, the tandem repeats(n) is within the standard limit (14-41) of heterogenic DNA. So, the sample is heteregenerous.

3. (2 marks) Ted just finished his PCR experiment and obtained the results in the

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