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Lab Report: What Is A Hydrate Anhydrous Compound?

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Introduction A hydrate is a chemical compound, where water molecules are chemically bonded to another compound or element, it has a specific number of water molecules, a compound that contains water as part of its crystal. Hydrates are are characterized by the number of moles of water molecules per mole of salt. When there is a chemical formula (CuSO4 . 5H2O) this means for every one formula unit (CuSO4) there is a certain number of water molecules (in this case 5 water molecules). An anhydrous compound is a compound that can form a hydrate but with all the water removed, usually by heat. A hydrate can become an anhydrous compound by heating. (For example CuSO4 . 5H2O would become CuSO4 because all the water has been removed.) When a hydrate …show more content…

xH2O was heated there was a colour change from blue to white, this is because the water was being removed because heat was added. Many compounds decompose when there heated, like this one this is why it is a decomposition reaction. The CuSO4 . 3H2O became CuSO4 + 3H2O the compound separated and became two separate compounds this is why this is a decomposition reaction. The crystals also changed form. Before heat the water was in the compound which made the crystals appear to be bigger rather then why it became an anhydrous when the heat was added and the water was removed which made the crystals appear smaller. Because the crystal changed from and colour this proves that there was water that has been removed to make this change. Error Analysis Some sources of error may have been that the water was not fully gone, and that the beaker may have still been hot when the mass was measured. …show more content…

xH2O was heated until all the water was removed. Calculate the percentage of water of hydration and the formula of the hydrate if the residue after heating weighed 2.495g. = 2.815 - 2.495 = 0.33 = 0.33 / 2.815 x 100 = 11.72% Give the correct name for the following: (NH4)2C2O4 . 5H2O --> Ammonium oxalate pentahydrate Cu(NO3)2 . H2o --> Copper nitrate monohydrate The mass percent of water in a hydrate of MnCl2 is 36.41%. What is the formula of the hydrate? = 125.84 / (1 - 0.3641) = 197.9 g/mol = 197.9 - 125.8 = 71.16 g = 71.16 g (1 mol / 18.01 g H2O) = 3.95 = = MnCl2 . 4H2O A 140.5g sample of NiSO4 . xH2O is heated until no further decrease in mass. The mass of the anhydrous salt is 77.5g. What is the formula of the hydrate? Calculate the percentage of

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