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Synthesis Of Lidocaine Lab Report

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Lidocaine (3) was prepared by nucleophilic substitution of α-chloro-2,6-dimethylacetanilide with 2(CH2H5)2NH (Scheme 3). Scheme 3. Synthesis of Lidocaine The yield of lidocaine was 17.3%. While the experimental yield was bad, a percent yield closer to 40-50% would have been a more realistic percent yield. Given the results, a significant amount of the product was lost during the reaction; likely, this occurred during transferring of mixtures between flasks. A portion of the product was also lost during recrystallization due to some of the product just not fully being recrystallized. The purity of the product was confirmed using melting points. Trial one of melting point was 64.3-67.9° C, while trial two of melting point was 66.2-68.3° …show more content…

During week one, dissolve ScCl2 H2O (50.920g, 0.0065mol, 1 equiv.) in concentrated hydrochloric acid (55mL) all in an Erlenmeyer flask, might need to heat for complete dissolution. In another Erlenmeyer flask dissolve 2,6-dimethylnitrobenzene (6.744g, 0.0045mol, 1.4 equiv.) in glacial acetic acid (70mL). Then add ScCl2 H2O to 2,6-dimethylnitrobenzene at one time, swirl shortly and let solution sit for 15 minutes. After time is up, cool reaction to room temperature with a water bath, then vacuum filtrate. Then transfer damp solid into an Erlenmeyer flask and add deionized water (40mL). Then turn mixture basic by adding KOH (8M, 40mL). After mixture is basic, cool mixture to room temperature in ice bath and transfer it to the separatory funnel and extract it with diethyl ether (2 x 15mL). Drain all of the organic layers into the same flask. Next wash the organic layer with deionized water (2 x 10mL) and then dry it with anhydrous magnesium sulfate. Gravity filtrate the solution and then rotary evaporate it. Transfer the evaporated solution into a culture tube and store with a loose cap. The following week weigh the product, which is 2,6-dimethylaniline, perform an IR, and 1H NMR. Yield: 2.832g (0.023mol, 47.1%). IR (neat): 1624 cm-1 (C=C), 3468 and 3386 cm-1 (N-H), 2967 cm-1 (C-H). 1H NMR (300 MHz, CDCl3): δ 2.68 (methyl groups off ring), 3.65 (NH2), 6.74, 7.03 (H’s on ring) …show more content…

During week three, dissolve α-chloro-2,6-dimethylacetanilide (2.202g, 0.011mol, 3 equiv.) in toluene (30mL) and a stir bar in a dry-round bottom flask. Assemble the apparatus for heating under reflux. Then add diethylamine (2.4g, 0.033mol, 1 equiv.) to the previous solution. Then heat the mixture under reflux for 90 minutes. After the reflux is complete let mixture cool to room temperature and then ice bath for a short period of time. Then vacuum filtrate the product and rinse the solid product with toluene (5mL). Then transfer the filtrate and washing to a separatory funnel and extract it with HCl (3M, 2 x 20mL). Then combine the acidic extracts in an Erlenmeyer flask and add KOH (8M, 25mL) to make solution basic. Cool the mixture in an Ice bath. Then transfer mixture to a separatory funnel extract it with diethyl ether (2 x 15mL). Then wash the organic extracts with deionized water (25mL) and then dry it with anhydrous sodium sulfate. Gravity filtrate the solution, and cover the beaker with a watch glass till the following week. The following week weigh the product, which is pure lidocaine, determine the melting point, and perform an IR. Yield: 1.360g (0.0058 mol, 17.3%). IR (neat): 1660 cm-1 (C=O), 3252 cm-1 (N-H), 2971 cm-1

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