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- Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory as a primary standard. It has the formula KHC8H4O4. This is often written in the short-hand notation as KHP. If 25.0mL of a potassium hydroxide solution are needed to neutralize 2.26g of KHP, what is the molarity of the potassium hydroxide solution? Potassium hydrogen phthalate sometimes called potassium biphthalate, as shown on this bottle is an acid that is convenient to store and use because it is a solid.Will the calculated Molarity of NaOH be too high or too low or unaffected if the following happen: When you answer the question, consider how the situation affects the calculation of molarity of NaOH and moles NaOH, which is calculated from the mass of KHP. For each answer, you must supply a clear explanation for your answer. Often times, students will restate the facts rather than explaining why they chose the answer they chose. a) You add the weighed KHP to a flask containing a 60mL of water rather than 50 mL of water. Explain. Your answer must contain a well-thought-out and clearly written explanation. b) The buret is still wet with water on the inside when you add your NaOH solution. Explain c) The KHP is wet when you weigh it. Explain. d) You titrate past the equivalence point by 0.50mL Answer a-dSuppose you want to prepare a solution of 2.50L of 1.00M HCL solution from concentrated 12.0 M HCl (aq.) How many liters of concentrated acid is needed and how many liters of water is needed?[Dimensional Analysis is appreciated!]
- 1)Calculate moles in sample 5.77 mg LiMgBr3 2) attached below [ plz do both plz do not give in complete solution ... if u plan to do only 1 then skip someone will do all , plz do both or else skip )A 12.7g sample of vinegar is titrated. It requires 19.75 mL of 0.205 M NaOH to neutralize the acetic acid (CH3COOH) in the vinegar. Calculate the weight percent (w/w) of acetic acid in the vinegar. Note: 1 mole of base neutralizes 1 mole of acid.A 6.00ml portion of an 8.00M stock solution is to be diluted to 0.400M. What will be the final volume after dilution?
- How do you prepare a 250-mL of 0.125 M NaOH solution? From solid NaOH pellets (by dissolving) From a solution of 0.745 M NaOH (by dilution) Please show complete Given, Required, and Solution! Thank you very much!What molarity of HCI stock solution is needed so that 2.5mL of this stock solutiondiluted to 0.025L will yield 25mM?9 g of ethyl alcohol is dissolved in 96 ml of water (density = 1.00 g/mL at 20 oC). What is the % w/w for the ethyl alcohol in the resulting solution?
- A 2.65% by mass solution of ZnCl2 dissolved in water contains 16.0g of ZnCl2. Calculate the mass of the water in this solution. pleas provide lines in between so we can cancel out. The answer is 588g. ue stiochemustry ptrovide step by steoPlease answer subparts a-c. Show solutionsIf one mixes 50cm³ of EtOH and 50cm³ of H2O at room temperature; will the total volume of the solution be 100.0 cm³? Justify answer with appropriate calculations and explanations