strength of materials question is imagec)? 1)- a) -Determine the normal stress at the midpoint of link BC knowing that it has a crosssectional are of 1x8 mm (see the figure below) b)- Determine the maximunm normal stress inLink BC knowing that pins at C and B have 5 mm diameters. c)- Determine the shearingstress in the pin at C (knowing that the pin is under double shear).2 kN1 kN130 mm100 mm1 kNB450

(c) Consider the diagram shown below for the given system.

1)- a) -Determine the normal stress at the midpoint of link BC knowing that it has a cross sectional are of 1x8 mm (see the figure below) b)- Determine the maximum normal stress in Link BC knowing that pins at C and B have 5 mm diameters. c)- Determine the shearing stress in the pin at C (knowing that the pin is under double shear).

1)- a) -Determine the normal stress at the midpoint of link BC knowing that it has a cross sectional are of 1x8 mm (see the figure below) b)- Determine the maximum normal stress in Link BC knowing that pins at C and B have 5 mm diameters. c)- Determine the shearing stress in the pin at C (knowing that the pin is under double shear).

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A flanged bolt coupling consists of ten 20-mm diameter steel bolts spaced evenly around a bolt circle 400 mm in diameter. Determine the maximum shear stress formed in a 200-mm diameter shaft if the allowable shearing stress in the bolts is 40 MPa. Show complete solution and figure.
Two steel springs arranged as shown support a load P. The left spring consists of 12 turns of 20-mm diameter wire on a mean diameter of 300 mm. The right spring has 10 turns of 16-mm diameter wire on a mean diameter of 200 mm. Calculate the maximum value of P and the total elongation if the allowable shearing stress is 200 MPa. Us the Exact formula. Answer: P = 1443.35 N
As shown in the figure, a homogeneous 50 kg rigid block is suspended by the three springs whose lower ends were originally at the same level. Each steel spring has 24 turns of 10 mm diameter on a mean diameter of 100 mm, and G = 83 GPa. The bronze spring has 48 turns of 20 mm diameter wire on a mean diameter of 150 mm and G = 42 GPA. Compute the shearing stress in each spring, use Wahl’s Equation.
The riveted lap connection shown consists of two(2) – PL 12 mm × 280 mm. 1. If allowable shearing stress in 20mm rivets is 186 MPa, find the maximum allowable force P that can be applied a. 233.734 kN b. 251.813 kN c. 283.406 kN d. 245.916 kN 2. If allowable bearing stress in holes is 1.2Fu where Fu is the ultimate strength of the plate and which is equal to 400 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 563.3 kN b. 460.8 kN c. 683. 6 kN d. 405.9 kN 3. If allowable yielding of gross area is Fy/1.67, where Fy is the yield strength of the plate and which is equal to 250 MPa, find the maximum allowable force P that can be applied neglecting effect of eccentricity. a. 534 kN b. 560 kN c. 446 kN d. 503 kN 4. If diameter of hole equals diameter of rivet, what is the net area of edge-3-4-edge in square…
A flexible cable and rigid boom system is used to lift a load of 65kN at the end of Boom at point C. Points A and B are considered pinned in nature. The allowable shearing stress at all bolts are 250MPa and the allowable bearing stress at all bolts are 300MPa. Note that the initial position of boom is horizontal and segment A and B are vertical. Determine the horizontal reaction at A. 3. Determine the vertical reaction at A.
Two steel springs arranged in series supports a load P. The upper spring has 12 turns of 20-mm-diameterwire on a mean radius of 100 mm. The lower spring consists of 10 turns of 25-mm diameter wire on amean radius of 75 mm. If the maximum shearing stress in either spring must not exceed 300 MPa,compute the maximum value of P and the total elongation of the assembly. Use approximation formulaand G = 83 GPa. Compute the equivalent spring constant by dividing the load by the total elongation.
n figure as shown below, assume that a 35mm diameter rivet joint the plates which are each 150mm wide.(a) if the allowable stresses 200 MPa for bearing in the plate material and 120MPa for shearing of the rivet, determine the minimum thickness of each plate.(b)Under the conditions specified in part (a) what is the largest average stress in the plate.
In the clevis shown in the figure, determine the minimum bolt diameter and minimum thickness of each yoke that will support a load P = 55kN without exceeding a shearing stress of 70 MPa and a bearing stress of 140 MPa
a. Determine the absolute maximum shear stress at segment AB (in MPa) b. Determine the absolute maximum shear stress at segment BC (in MPa) c. Determine the angle twist of Gear C relative to A (in degrees) note: indicate the free body diagram
Define the terms shear stress and shear strain, illustrating your answer by means of a simple sketch. Two circular bars, one of brass and the other of steel, are to be loaded by a shear load of 30 KN. Determine the necessary diameter of the bars (a) in single shear, (b) in double shear, if the shear stress in the two materials must not exceed 50 MN/m² and 100 MN/m² respectively. Ans: [27.6, 19.5, 19.5, 13.8mm.]
For the pin-connected structure in the figure, determine the minimum diameter for the pin at joint D if the average shearing stress in the pin must be limited to 8,200psi.
Two steel springs with plain ends are arranged in series and supports a load. The upper spring has 12 turns of 27-mm-diameter wire on a mean diameter of 200 mm. The lower spring consists of 8 turns of 20-mm diameter wire on a mean diameter of 150 mm. The maximum shearing stress in either spring must not exceed 217 MPa. Use G = 83 GPa. Calculate the maximum value of force acting on the upper spring alone in N.