Question
Asked Aug 1, 2019
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The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.12 mA out of the page, and is at distance d1 = 2.47 cm from a surface. Wire 2, which is parallel to wire 1 and also long, is at horizontal distance d2 = 5.29 cm from wire 1 and carries a current of 6.81 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1?

1
-dg
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1 -dg

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Expert Answer

Step 1

The magnetic force per unit length on wire 2 due to wire 1, will be:

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x I2 27TV(d)2(d2)2, F B x I2 = is the force per uit length where, B is the magnetic field at wire 2 due to wire 1 and, I2 is the current in wire 2. Vd,)2+(d2)2

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Step 2

Thus, the x-component of the magnetic force per un...

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F cose l d2 X or, 2(d)2 (d2) (d,) (d2) or, 2TT[(d1)2(d2)2] 4Tt X 10-7 x 4.12 x 10-3 x 6.81 x 10-3 x 5.29 x 10-2 F. or, (5.29 x 10-2)?] 2T[(2.47 x 10-2)2 N = 8.7089 x 10(-11) m or, OP

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Magnetic Effects of Current

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