(1) The given program outputs a fixed-height triangle using a * character. Modify the given program to output a right triangle that instead uses the user-specified triangleChar character.   (2) Modify the program to use a nested loop to output a right triangle of height triangleHeight. The first line will have one user-specified character, such as % or *. Each subsequent line will have one additional user-specified character until the number in the triangle's base reaches triangleHeight. Output a space after each user-specified character, including after the line's last user-specified character.   Example output for triangleChar = % and triangleHeight = 5:

Write a program that uses for statements to print the following patterns separately, one below the other. Use for loops to generate the patterns. All asterisks (*) should be printed by a single statement of the form cout << '*'; (this causes the asterisks to print side by side).  [Hint: The last two patterns require that each line begin with an appropriate number of blanks. Extra credit: Combine your code from the four separate problems into a single program that prints all four patterns side by side by making clever use of nested for loops.] (Drawing Patterns with Nested for Loops) Write a program that uses for statements toprint the following patterns separately, one below the other. Use for loops to generate the patterns. All asterisks (*) should be printed by a single statement of the form cout << '*'; (this causes the asterisks to print side by side).  [Hint: The last two patterns require that each line begin with an appropriate number of blanks. Extra credit: Combine…

Write code to complete DoublePennies()'s base case. Sample output for below program with inputs 1 and 10: Number of pennies after 10 days: 1024 Note: If the submitted code has an infinite loop, the system will stop running the code after a few seconds, and report "Program end never reached." The system doesn't print the test case that caused the reported message       #include <stdio.h> // Returns number of pennies if pennies are doubled numDays timeslong long DoublePennies(long long numPennies, int numDays){long long totalPennies; /* Your solution goes here */ else {totalPennies = DoublePennies((numPennies * 2), numDays - 1);} return totalPennies;} // Program computes pennies if you have 1 penny today,// 2 pennies after one day, 4 after two days, and so onint main(void) {long long startingPennies;int userDays; scanf("%lld", &startingPennies);scanf("%d", &userDays);printf("Number of pennies after %d days: %lld\n", userDays, DoublePennies(startingPennies, userDays));…

Write a FUNCTION that asks the user to input a string. Unless the user inputs "END" or "end", a loop will execute wherein the user is asked to input a string. Each time the loop runs and the user input a string, the function does the following: +Print the number of letters in the string that the user inputs; +Print the number of digits in the string that the user inputs. When the user enters "END" or "end" the loop stops and the function prints the aggregate numbers of letters and digits that the user has entered from the beginning. Example: 1st loop: a8K6H => 3 letters and 2 numbers 2nd loop: THGF*T425 => 5 letters and 3 numbers Aggragates: 8 letters and 5 numbers