If 24.0 ml of 0.0100 M KMNO4 solution is needed to titrate 1.00 g of a sample of H2C204 to the equivalence point, what is the percent by mass of H2C204 in the sample? The net ionic equation is: 2MNO,¯ + 6H* + 5H,C,04 - 2Mn2- + 10cO2 + 8H20 O 54.0 % O 2.40 % O 5.40 % O 3.69 %

Chemistry: Principles and Reactions
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Chapter4: Reactions In Aqueous Solution
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Problem 78QAP: When 85.0 mL of 0.250 M Ba(OH)2 solution is added to 85.00 mL of 0.250 M Al (NO3)3 solution, a white...
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If 24.0 ml of 0.0100 M KMNO4 solution is needed to titrate 1.00 g of a sample of H2C204 to the equivalence
point, what is the percent by mass of H2C204 in the sample? The net ionic equation is:
2MNO, + 6H* + 5H2C204 – 2MN²+ + 10CO2 + 8H20
O 54.0 %
O 2.40 %
O 5.40 %
3.69 %
Transcribed Image Text:If 24.0 ml of 0.0100 M KMNO4 solution is needed to titrate 1.00 g of a sample of H2C204 to the equivalence point, what is the percent by mass of H2C204 in the sample? The net ionic equation is: 2MNO, + 6H* + 5H2C204 – 2MN²+ + 10CO2 + 8H20 O 54.0 % O 2.40 % O 5.40 % 3.69 %
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