1. excess CH3/К2СОЗ 2. Ag20, H20 1. еxcess CH3l/K-CОЗ 2. Ag20, H20 CH3NCH,CH,CH2CH=CH2 3. CH2=CHCH,CH=CH2 1,4-pentadiene 3. Д `N' ČH3 Н piperidine
1. excess CH3/К2СОЗ 2. Ag20, H20 1. еxcess CH3l/K-CОЗ 2. Ag20, H20 CH3NCH,CH,CH2CH=CH2 3. CH2=CHCH,CH=CH2 1,4-pentadiene 3. Д `N' ČH3 Н piperidine
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter6: Alkanes & Alkenes
Section: Chapter Questions
Problem 33CTQ
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Question
When piperidine undergoes the series of reactions shown here, 1,4-pentadiene is obtained as the product. When the four different methyl- substituted piperidines undergo the same series of reactions, each forms a different diene: 1,5-hexadiene; 1,4-pentadiene; 2-methyl-1,4-pentadiene; and 3-methyl-1,4-pentadiene. Which methyl-substituted piperidine forms which diene?
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