1.13 A couple M of magnitude 1500 N m is applied to the crank of an engine. For the position shown, determine (a) the force P required to hold the cngine system in equilibrium, (b) the average normal stress in the connecting rod BC, which has a 450- mm? uniform cross section. Problem 1.13 P Use piston, rod, and crank together as free bady. Add wall reaction H and bearing reactions Ax and Ay. 200 nm

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Why is the wall reaction on the left side not considered in the calculation of force P

1.13 A couple M of magnitude 1500 N m is applied to the crank of an engine. For
the position shown, determine (a) the force P required to hold the cngine system in
equilibrium, (b) the average normal stress in the connecting rod BC, which has a 450
imm“ uniform cross section.
Problem 1.13
Use piston, rod, and crank
together as free bady. Add
wall reaction H and bearing
reactions Ax and Ay.
Đ ZMA
200 unm
80 mm
O:
- W
(0.280 m) H - 1500 N-m
H = 5.3571 ×103 N
60 mm
AY
Use piston alone as free
body! Note +that rod is
a two-force mem ber; hence the dineotion
of force Fec is known.. Draw the fovce
triangle and sodve fon P and Fae by
proportions.
Fec
Fes
l=/ 200
+.60°
208.81
m un
200
200
60
17. 86 x103 N
60
H.
P= 17. 86 kN
(a)
Fac
H.
208.81
60
FBe = 18.643 ×10 N
Σ
Transcribed Image Text:1.13 A couple M of magnitude 1500 N m is applied to the crank of an engine. For the position shown, determine (a) the force P required to hold the cngine system in equilibrium, (b) the average normal stress in the connecting rod BC, which has a 450 imm“ uniform cross section. Problem 1.13 Use piston, rod, and crank together as free bady. Add wall reaction H and bearing reactions Ax and Ay. Đ ZMA 200 unm 80 mm O: - W (0.280 m) H - 1500 N-m H = 5.3571 ×103 N 60 mm AY Use piston alone as free body! Note +that rod is a two-force mem ber; hence the dineotion of force Fec is known.. Draw the fovce triangle and sodve fon P and Fae by proportions. Fec Fes l=/ 200 +.60° 208.81 m un 200 200 60 17. 86 x103 N 60 H. P= 17. 86 kN (a) Fac H. 208.81 60 FBe = 18.643 ×10 N Σ
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