10.5mL (mw 106) of benzaldehyde and 2.9g(3.63mL, mw 40) of acetone react with 5g of NaOH and 25mL of Ethanol to form 6.7g of Dibenzalacetone. What is the theoretical, actual and percent yield
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10.5mL (mw 106) of benzaldehyde and 2.9g(3.63mL, mw 40) of acetone react with 5g of NaOH and 25mL of Ethanol to form 6.7g of Dibenzalacetone. What is the theoretical, actual and percent yield?
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