Ethyl alcohol (C2H5OH) may be prepared by the fermentation of glucose (C6H12O6) as indicated by the equation: yeast C6H12O6 ----> C2H5OH + CO2 74.12 mL of ethyl alcohol (specific gravity = 0.790) was collected by this fermentation pro- cess. What mass of glucose was used?
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- Ethyl alcohol (C2H5OH) may be prepared by the fermentation of glucose (C6H12O6) as indicated by the equation:
yeast
C6H12O6 ----> C2H5OH + CO2
74.12 mL of ethyl alcohol (specific gravity = 0.790) was collected by this fermentation pro- cess. What mass of glucose was used?
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- Ethyl alcohol (C2H5OH) may be prepared by the fermentation of glucose (C6H12O6) as indicated by the equation: yeastC6H12O6 ----> C2H5OH + CO2 74.12 mL of ethyl alcohol (specific gravity = 0.790) was collected by this fermentation pro- cess. What mass of glucose was used?A spent 1.0 percent caustic soda solution (ρNaOH = 8.42 lb/gal) with a volumetric flow rate of 3.0gpm is to be neutralized using either sulfuric acid or hydrochloric acid. First, determine the massflow rate (lb/day) of NaOH in the spent caustic soda solution, and then use that value todetermine the stoichiometric amounts (lb/day) of:1. H2SO4 required for neutralizing the OH− ions contributed by the spent caustic soda.[Hints: (1) write the balanced chemical equation for the acid-base reaction betweenNaOH and H2SO4, and use it to establish the stoichiometric weight ratio H2SO4 : NaOH.]2. HCl required for neutralizing the OH− ions contributed by the spent caustic soda. [Hints:(1) write the balanced chemical equation for the acid-base reaction between NaOH andHCl and use it to establish the stoichiometric weight ratio HCl : NaOH.]In the distillation of the mixture of acetic acid (MW=60.05 g/mole; d=1.05g/ml) and water (MW= 18.00 g/mole; 1.00 g/ml), a total of 0.028 Liters of 1.0 M std NaOH was used to reach the endpoint of a 23 ml of distillate. What is the mole ratio of the CH3COOH in the mixture? final answer in 3 decimal places.
- What is the molarity of a concentrated solution of sulfuric acid with a specific gravity of 1.84 and 95.0% by weight sulfuric acid? specific gravity = density of substance at certain temp/density of water at 4 degrees C the density of water is 0.999973 g/mL at 4 degrees celsius. Describe how to prepare 3.0 L of 0.100M. I will pipet ______ and add this to 200mL water. The solution will be stirred and diluted to 3L with water.A 700 cu ft tank contains 17lb of C2H6 and 9lb of CH4 at 50F. What is the specific gravity of the mixture?A stock solution of 75% v/v ethanol was diluted with distilled water to prepare 1L of 42% v/v ethanol. (Density of ethanol = 0.789 g/mL; MW of ethanol = 46 g/mol). Determine the initial volume (in mL) of 75% v/v ethanol used in the preparation. Final answer should NOT contain any unit. Type the VALUE only. Please observe 0 decimal places.
- There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…There's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…Downvoted for wrong solution. A river is carrying water containing 2000 mg/l Magnesium Chloride into a small lake. The lake has a naturally occurring Magnesium Chloride of 50 mg/l. If the river flow is 2500 Lmin and the lake flow rate is 1.5 m³.sec¹, what is the concentration of MgCl2 in the lake after the discharge point? Assume that the flows in the river and lake are completely mixed, that the salt is a conservative substance, and the system is at steady state.
- 10.5mL (mw 106) of benzaldehyde and 2.9g(3.63mL, mw 40) of acetone react with 5g of NaOH and 25mL of Ethanol to form 6.7g of Dibenzalacetone. What is the theoretical, actual and percent yield?A mixture of ethanol (ethyl alcohol) and water contains 40.0% water by mass.(a) Assuming volume additivity of the components, estimate the specific gravity of themixture at 20°C. What volume (in liters) of this mixture is required to provide 150 mol ofethanol?(b) Repeat Part (a) with the additional information that the specific gravity of the mixture at20°C is 0.89045 (making it unnecessary to assume volume additivity). What percentage errorresults from the volume-additivity assumption?A sample of a soil was analysed for K+ as follows. A 2.50 g sample of soil was dissolved in acid and diluted to volume in 100 mL volumetric flask. A 10 mL of the resulting solution was transferred by pipet to a 50 mL volumetric flask and diluted to volume. An analysis showed that the concentration of K+ in the final solution was 9.81 ppm. What was the weight percent of K+ in the original soil?