13C NMR Spectrum (50.0 MHz, CDCl 3 solution) DEPT CH2 CH 3 CH↑ proton decoupled solvent 200 160 120 80 40 0 8 (ppm) 1H NMR Spectrum (200 MHz, CDCl 3 solution) f 10 9 8 7 6 5 4 3 2 1 92 22 TMS 0 8 (ppm) 100 80 60 40 20 IR Spectrum (liquid film) 2984 1741 1243 4000 3000 2000 1600 1200 800 0.0 V (cm³) 'ויויויזיוידיוידי % of base peak 43 29 M** = 88 Mass Spectrum 0.5 Problem 3 UV spectrum 1.0 solvent ethanol 15.4 mg/10 mis path length: 1.00 cm C4H8O2 1.5 40 80 120 160 200 240 280 200 250 300 350 m/e λ (nm) 13C NMR Spectrum (50.0 MHz, CDCl 3 solution) DEPT CH 2 CH 3 CH↑ proton decoupled solvent 200 160 120 80 60 40 40 ル 0 8 (ppm)

13C NMR Spectrum (50.0 MHz, CDCl 3 solution) DEPT CH2 CH 3 CH↑ proton decoupled solvent 200 160 120 80 40 0 8 (ppm) 1H NMR Spectrum (200 MHz, CDCl 3 solution) f 10 9 8 7 6 5 4 3 2 1 92 22 TMS 0 8 (ppm) 100 80 60 40 20 IR Spectrum (liquid film) 2984 1741 1243 4000 3000 2000 1600 1200 800 0.0 V (cm³) 'ויויויזיוידיוידי % of base peak 43 29 M** = 88 Mass Spectrum 0.5 Problem 3 UV spectrum 1.0 solvent ethanol 15.4 mg/10 mis path length: 1.00 cm C4H8O2 1.5 40 80 120 160 200 240 280 200 250 300 350 m/e λ (nm) 13C NMR Spectrum (50.0 MHz, CDCl 3 solution) DEPT CH 2 CH 3 CH↑ proton decoupled solvent 200 160 120 80 60 40 40 ル 0 8 (ppm)

Principles of Instrumental Analysis

7th Edition

ISBN:9781305577213

Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch

Chapter34: Particle Size Determination

Section: Chapter Questions

Problem 34.13QAP

See similar textbooks

Similar questions

Q) water hardness of each trial and average ppm with calculation, please. Hard Water Trial 1 Hard Water Trial 2 Hard Water Trial 3 Initial Syringe Reading 1.0ml 1.0ml 1.0ml Final Syringe Reading 0.88ml 0.84ml 0.85ml Volume of EDTA Consumed 0.12ml 0.16ml 0.15ml Water Hardness ppm CaCO3 Average ppm
Table 1. Data for the Concentration of the KMnO4 Unknown Solution. Abs of Unknown Solution is 0.362 Absorbance Concentration Trial 1 0.120 0.00145 Trial 2 0.066 0.00104 Unknown Solution: __________ What is the Concentration of the Unknown Solution. _____________ Show statistical treatment of data.
Column Plate Number: 16Retention Factor: 3.1Sample Peak Retention Time: 1.2minutesSample Peak Width: 1.53First Peak Retention Factor: 2.10Second Peak Retention Factor: 1.37Efficiency: 0.43Pressure: 375barrColumn: 28cm x 5mmViscosity: 2.3poiseFlow Rate: 1.2Column Permeability: 2.8 FIND: a & ba. Resolution b. Pressure if flow rate is adjusted to 2.3 c. Particle Size d. Selectivity Factor e. The retention time of the unretained peak
liquid-liquid extraction(LLE)Principles
What effect will the following have on plate height (H). Make sure to explain your full and complete reasoning. Increasing stationary phase thickness. Reducing the rate of sample injection. Increasing mobile phase flow rate. Decreasing temperature. Reducing stationary phase particle size.
A 0.0200 gram blood sample was decomposed by a microwave digestion technique followed by dilution to 100.0 mL in a volumetric flask. Aliquots of the sample solution were treated with a lead complexing reagent and water as follows: Solution 1: 10.0 ml blood sample + 20.0 mL complexing agent + 30.0 mL H20. Solution 2: 10.0 ml blood sample + 20.0 mL complexing agent + 26.0 mL H20 + 4.00 mL of 78 ppb Pb2+ standard. The resulting solutions were analyzed by UV/Vis at 375 nm. Absorbance for solution 1 = 0.155 and for solution 2 = 0.216. Calculate the concentration of lead (ppb) in the original sample.
A new method is proposed to simultaneously detectand separatefour foodadditives by reversed-phase liquid chromatography. The data were obtained using theliquid chromatographic column with a flow rate of 0.5 mL per min and with the followingparameters: Pore size 100 A Particle Size 3.5 Internal diameter 4.6 mm Length 150 mm The food additives found in the sample resulted in the following data: ( see image for table) a.Calculate the number of plates from each peak. b.Calculate the plate height for the column. c.Retention factor for each peak.
Calculate the amount of phycocyanin in Sample 1 in mg where A620=0.211 and A650=0.086, taking into account the dilution factor as per question 6 (100ul), and the total volume of extract as per question 4 (140ml) . Note your answer to 2 decimal places
The original solution was diluted by a factor of three, and then the absorbance of the diluted cereal sample solution was measured and recorded as (2.0x10^-1). Use the following trendline and dilution factor to determine the concentration of iron, in unit of M, in the original cereal sample solution. The trendline (linear regression) as displayed on the plot is y = 11898x - 0.0112.
A fly ash aerosol of monodisperse particles with a density of 2.0 g/mL and particle diameter of 10.0 mm has a concentration of 1000.0 mg/m3. Calculate the settling velocity in cm/s and the settling rate in g/m2-s. Please answer very soon will give rating surely
Column length: 25.0 cm Column diameter: 0.46 cm Stationary phase: C-18 Mobile phase: 80% methanol in water Flow rate: 1.0 mL/min Dead time: 5 min Peak width at base, WA = 20 Peak width at base, WB = 24
A spectrophotometric method for the quantitative determination of the concentration ofPb2+ in blood yields an Ssamp of 0.133 for a 1 mL sample of blood that has been diluted to 6 mL. A second sample is spiked with 1 µL of a 1467 ppb Pb2+ standard and diluted to 6 mL, yielding an Sspike of 0.491. Determine the concentration of Pb2+ in the original sample of blood.