14.44 The dissociation of molecular i0dine into iodine at- oms is represented as L(g) = 21(g) At 1000 K, the equilibrium constant K. for the reaction is 3.80 × 10¬³. Suppose you start with 0.0456 mole of I, in a 2.30-L flask at 1000 K. What are the concentrations of the gases at equilibrium?

Principles of Modern Chemistry
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Chapter14: Chemical Equilibrium
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14.44 The dissociation of molecular iodine into iodine at-
oms is represented as
L(g) = 21(g)
At 1000 K, the equilibrium constant K. for the
reaction is 3.80 × 10¬³. Suppose you start with
0.0456 mole of I, in a 2.30-L flask at 1000 K. What
are the concentrations of the gases at equilibrium?
Transcribed Image Text:14.44 The dissociation of molecular iodine into iodine at- oms is represented as L(g) = 21(g) At 1000 K, the equilibrium constant K. for the reaction is 3.80 × 10¬³. Suppose you start with 0.0456 mole of I, in a 2.30-L flask at 1000 K. What are the concentrations of the gases at equilibrium?
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