14000 1.435 12000 1.430 10000 1.425 8000 1.420 6000 1.415 4000 1.410 2000 1.405 1.400 45 15 20 25 30 35 40 Temperature ["C] +dynamic viscosity ImPas) density [g/cm") Figure 1 (a) As shown in Figure 1, viscosity and density of honey was found to decrease with increase in temperature. Explain the reasons behnd these phenomenon related to Fluid Mechanics in microscopic view. Dynamic viscolsty [mPa.s] Density [g/cm]

14000 1.435 12000 1.430 10000 1.425 8000 1.420 6000 1.415 4000 1.410 2000 1.405 1.400 45 15 20 25 30 35 40 Temperature ["C] +dynamic viscosity ImPas) density [g/cm") Figure 1 (a) As shown in Figure 1, viscosity and density of honey was found to decrease with increase in temperature. Explain the reasons behnd these phenomenon related to Fluid Mechanics in microscopic view. Dynamic viscolsty [mPa.s] Density [g/cm]

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter1: Introduction To Statics

Section: Chapter Questions

Problem 1.10P: A differential equation is d2ydt2=Ay2+Byt where y represents a distance and t is time. Determine the...

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Industries involved in viscosity measurement [27, 29] continue to use the CGS system ofunits, since centimeters and grams yield convenient numbers for many fl uids. The absoluteviscosity ( μ ) unit is the poise, named after J. L. M. Poiseuille, a French physician who in1840 performed pioneering experiments on water fl ow in pipes; 1 poise =1 g/(cm-s). Thekinematic viscosity ( ν ) unit is the stokes, named after G. G. Stokes, a British physicist whoin 1845 helped develop the basic partial differential equations of fl uid momentum; 1 stokes =1 cm 2 /s. Water at 20 ° C has μ ~~ 0.01 poise and also ν ~~ 0.01 stokes. Express these resultsin ( a ) SI and ( b ) BG units.
The viscosity of a light mineral oil is tested by the settlings sphere method given the following data calculate the viscosity drop equals 61.5 cm time of drop equals 2.1 second density of oil equals 0.838 g/mL density of sphere equals 1.89 g/cm^3. Radius of sphere equals 0.80 cm.
Which of the following is FALSE regarding the continuum assumption of fluids? Select one: a. Uncertainties within the molecular properties of the fluid will be neglected b. Limit concepts can be applied on fluids c. Fluids with same composition may have different properties d. The fluid will be analyzed in the macroscopic level Which of the following does NOT describe a difference between liquids and gases? Select one: a. Liquids form a free surface while gases do not b. Liquids have lower bulk modulus of elasticity than gases c. Specific gravities of liquids are higher than gases d. Viscosity of liquids decreases as temperature increases while on gases, viscosity increases with temperature
explain briefly the significance of each of the following parameters:
Case 1: Material system without density and viscosity differences Though unlikely in real life, in this case, we assume that all of the material in the homogenizer is of the same density and viscosity. Thus, only one set of material parameters are mentioned (density, ρ; dynamic viscosity, μ). The important parameters are listed as follows: Target quantity : Mixing time, θ Geometric parameters : Stirrer diameter, d Material parameters : Density, ρ Dynamic viscosity, μ Process-related parameters : Stirrer speed, n 1.1) Write out the relevance list for Case 1. 1.2) Generate the pi-set for this case. 1.3) Write out the appropriate pi (π) numbers from the generated pi-set. 1.4) Identify the established dimensionless numbers from the derived pi (π) numbers. 1.5) Write the possible relationship of the dimensionless numbers for Case 1.
A core was mounted in a gas permeameter to measure permeability. Determine the liquid permeability (mD) of the core using gas (in oilfield units). The laboratory data are as follows: Diameter of the core = 3.78 cm Length of the core = 7.63 cm Gas viscosity = 0.0148 cP Flow rate = 9.07 cm3/s P1 = 1.439 atm P2 = 1.086 atm
Question 1 (a) Explain what you understand by the term Callibration. (b) Describe in details the process of calibrating a digital industrial thermometer. Question 2 (a) Explain the importance of Primary, secondary and tertiary standards employed in Metrology. (b) By giving appropriate examples outline the advantages and disadvantages of Line and end standards. Question 3 Describe the types of errors and defects encountered in measuring instruments used in metrology.
It is essential in engineering to consider measurement uncertainty when analysing data. Describe the types of uncertainties that can occur when taking measurements, how to assess them and what affect this can have on thepresentation of data. Include diagrams
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(a) Verify that each additive term in the Bernoulli equation has the same dimensions. (b) What are the dimensions of the constant C? (a) Verify that each additive term in the Bernoulli equation has the same dimensions. (b) What are the dimensions of the constant C?
Cal. the permeability number of a sand specimen if it takes 75s to pass 2000 cm3 of air at a pressure of 6 g/cm2 through the standard sample.
The Reynolds number is a dimensionless group defined as follows for a liquid that flows through a pipe: Re = Dvρ / μ where D is the diameter of the pipe, v is the velocity of the fluid, ρ is its density and µ its viscosity. When the Reynolds number value is less than 2100, the flow is laminar, that is, the liquid it moves in lines of smooth flow. For Reynolds numbers greater than 2100, the flow is turbulent, characterized by considerable agitation. Liquid Methyl Ethyl Ketone (MEK) flows through 2067 '' ID tubing and through an average velocity of 0.48 ft / s. If the fluid temperature is 20 ° C, the density of the MEK The liquid is 0.805 g / cm and the viscosity is 0.43 cP (1 cP = 1.00 x 10 kg / (m-s)]. Determine the Reynolds number for MEK flow conditions. (Round the final result to a whole number without decimals).