19. An electron in a vacuum tube acquires a velocity of 5.3 X 10 cmls in a distance of 0.25 cm. Find the acceleration of the electron.

An Introduction to Physical Science
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Chapter10: Nuclear Physics
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v = d = df – di . a = v = vf – vi .
t t f – t I t t f – ti
vf = vi + a t v = ½ ( vf + vi )
d = ½ ( vf + vi ) t d = vi t + ½ a t2
vf2 = vi2 + 2 a d

19. An electron in a vacuum tube acquires a velocity of 5.3 X 10® cmls in a distance of 0,25 cm. Find the
acceleration of the electron.
Transcribed Image Text:19. An electron in a vacuum tube acquires a velocity of 5.3 X 10® cmls in a distance of 0,25 cm. Find the acceleration of the electron.
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