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University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185
BuyFindarrow_forward

University Physics Volume 3

17th Edition
William Moebs + 1 other
ISBN: 9781938168185
Textbook Problem

The 3.20-km-lfmg SLAC produces a beam of 50.0-GcV electrons. If there are 15,000 accelerating tubes, what average voltage must be across the gaps between them to achieve this energy?

To determine

The average voltage across the gaps.

Explanation

Given:

Potential energy, PE=50.0GeV

N = 15000

Formula used:

The average voltage can be calculated by

  V=PEq

Calculation:

1 V of potential difference can create potential energy of 1eV for an electron or a photon, then for q electrons, the potential energy will be PE=qV

Rearrange the above expression V=PEq

The net potential difference in SLAC is calculated as

Substitute 50.0GeV for PE and 1.6×1019C for q in the above equation.

  V=50.0GeV1.6×1019C

  V=50.0GeV×1.6× 10 19C1eV1

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