2) The state of stesss at a point in a body relative to the xyz coordinate system is:2 3 -5[o]= 32 kpsi6.%3D-5 2 -4a) Determine the principle stresses and the direction cosines corresponding to each principle stress.b) Draw the 3D Mohr's circles.c) Determine the maximum shear stress.d) Find the orientation of the plane containing the maximum shear stress relative to the original axissystem3) For the stress tensor in problem 2:a) Determine the normal and shear stress on a surface intersecting a plane defined by 3 points (0,0,0);(2,-1,3); (-2,0,1)b) Give the magnitudes of these stresses and the direction cosines defining their directions.

Answered: Image /qna-images/answer/a094b54f-6ca5-40cd-aea2-6f8420ef4347.jpg

Answered: 2) The state of stesss at a point in a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A stress element in a rock mass making up a slope experiences a 2D stress as follows: σx = 8 MPa, σy = 4 MPa , tauxy = 3 MPa a. Draw the Mohr circle. On Mohr's circle, mark the location of the x and y planes, mark the angle of rotation θ from the x plane to the σ₁,σ3,and taumax plane. Prove that the angle of rotation of the Mohr circle is 2 times the angle of rotation of the element. b. Write down the coordinates of the center of Mohr's circle and calculate its radius.
The state of stress at a point can be described by σx = 40 MPa , σy = 64 MPa , and τxy = 18 MPa . A second coordinate system is rotated by θ = 25 ∘ A) What is the normal stress in the direction of the x′-axis? B) What is the shear stress in the y′-direction for the faces with a normal in the x′-direction? C) What is the normal stress in the direction of the y′-axis?
For the plane-stress condition given below: σx = 400 MPa σy = 500 MPa τxy = - 30 MPa Construct a Mohr’s circle of stress, find: (a) the principal stresses and the orientation of the principal axes relative to the x,y axes (b) determine the stresses on an element, rotated in the x-y plane 60° counter?clockwise from its original position ; Show these stresses on a sketch of an element oriented at this angle (c) Also, using the matrix transformation law to compare the solutions with Mohr’s circle
Choose the correct answer Stress divided by Rate of strain is: d. Velocity a. Surface tension f. Kinematic viscosity b. Density e. Dynamic Viscosity c. Unit less
2. A figure shows a state of stress; determine the shearing stresses and normal stressesafter the element has been rotated (a) 40° clockwise, (b) 25° counterclockwise.
Choose correct answer: Maximum stress on a principle plane is Tangential stress shear stress Normal Stress Resultant stress
A plane stress state is given by the principal stresses σx =25 MPa and σy= -11 MPa. Determine σx' in the case that the system is inclined by 30 degrees (counter-clockwise). Give your answer in MPa to the nearest whole number.
Can you explain this part please? How you got 412.72? Stress = force/area Stress = 4849 (N)π412.72 (mm2) Stress = 38.29 MPa
I can't seem to find the shear stress at point b. Here's my work for reference.
find the principal stress , maximum in plane shear stress , average normal stress specdify the orientation of the element in each case , use mohrs circle to solve the question .
The principal tensile stress at a point across two mutually perpendicular planes are 100 N/mm2 and 40 N/mm2. The normal, tangential and resultant stresses on a plane inclined at 20° to the axis of the minor principal stress by analytical method is
Consider a certain critical point in a stress element. On a vertical plane, the compressive stress is 115 MPa and the shear stress is 31.5 MPa. There is no normal stress on the horizontal plane. Find the stresses acting on the principal planes and the orientation of principal planes with the horizontal plane. You may need to draw a Mohr circle.

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