2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of 0.22 A field current of 10 A produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open- circuit. Calculate the full-load regulation at p.f. 0.8 lag. [34.4%) og Rombay Unir 1978R)

2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of 0.22 A field current of 10 A produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open- circuit. Calculate the full-load regulation at p.f. 0.8 lag. [34.4%) og Rombay Unir 1978R)

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.13P

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Question

Full solutions for the problem with explanation please

2. A 500-V, 50-kVA, 1-0 altermator has an effective resistance of0.20. A field current of 10 A
produces an armature current of 200 A on short-circuit and an e.m.f. of 450 V on open-
circuit. Calculate the full-load regulation at p.f. 0.8 lag.
[34.4%)
(Flectrical Technology, Bombay Univ. 1978)

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