2. An aluminum rod is 1.5 m long. For aluminum, Young's Modulus is E = 70 GPa. An axial force of 3 kN is applied. The rod must not stretch more than 1 mm, and the normal stress must not exceed 40MPA. Determine the required diameter of the rod. (Hint: must check both conditions.)

2. An aluminum rod is 1.5 m long. For aluminum, Young's Modulus is E = 70 GPa. An axial force of 3 kN is applied. The rod must not stretch more than 1 mm, and the normal stress must not exceed 40MPA. Determine the required diameter of the rod. (Hint: must check both conditions.)

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.5P: An aluminum bar has length L = 6 ft and diameter d = 1.375 in. The stress-strain curse for the...

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

2. An aluminum rod is 1.5 m long. For aluminum, Young's Modulus is E = 70 GPa. An axial
force of 3 kN is applied. The rod must not stretch more than 1 mm, and the normal stress must
not exceed 40MPA. Determine the required diameter of the rod. (Hint: must check both
conditions.)
Ans: d = 9.77 mm

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