2N2 (g) + 502 (g) -- 2N2O5 (g) + 86.4 Joule T= 200°C P= 2 atm increase in concentration of O2 A. Backward addition of Cao to remove N205 B. No shift C. Forward increase in concentration of N2O5

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Chapter13: Fundamental Equilibrium Concepts
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2N2 (g) + 5O2 (g) ↔ 2N2O5 (g) + 86.4 Joule           T = 200°C   P = 2 atm

2N2 (g) + 502 (g) → 2N2O5 (g) + 86.4 Joule
T= 200°C P= 2 atm
v increase in concentration of 02
A. Backward
addition of Cao to remove N205
B. No shift
v increase in concentration of N205
C. Forward
decrease in the volume
increase in the concentration of N2
v decrease in the pressure
v change in temperature to 350°C
addition of Ne, an inert gas
v addition of H2 to neutralize N2
B. v addition of a positive catalyst
Transcribed Image Text:2N2 (g) + 502 (g) → 2N2O5 (g) + 86.4 Joule T= 200°C P= 2 atm v increase in concentration of 02 A. Backward addition of Cao to remove N205 B. No shift v increase in concentration of N205 C. Forward decrease in the volume increase in the concentration of N2 v decrease in the pressure v change in temperature to 350°C addition of Ne, an inert gas v addition of H2 to neutralize N2 B. v addition of a positive catalyst
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