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Exercise (3-2): find Fourier series on [0,2n] Question Answer (1) f(x) = x/2 sin nx (2) f(x)=-x 25 sin nx (3) f(x)= sinx sin x (4) f(x) = cosx COS X (5) f(x)=xsin x -1+ COS nX (6) f(x) = xcos x 2n(-1) (n-1)(n+1) %3D sin(nx) 0. 7) f(x) = 0

Exercise (3-2): find Fourier series on [0,2n] Question Answer (1) f(x) = x/2 sin nx (2) f(x)=-x 25 sin nx (3) f(x)= sinx sin x (4) f(x) = cosx COS X (5) f(x)=xsin x -1+ COS nX (6) f(x) = xcos x 2n(-1) (n-1)(n+1) %3D sin(nx) 0. 7) f(x) = 0

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Exercise (3-2): find Fourier series on [0,2n] Question Answer (1) f(x) = x/2 sin nx (2) f(x)=-x 2 sin nx (3) f(x)= sin x sin x (4) f(x) = cosx COS X (5) f(x)=xsin x -1+ COS nX (6) f(x)=xcos x 2n(-1) %3D sin(nx) (n-1)(n+1) 0. 7) f(x) = 0<xくて 1 l-(-1)" sin nx 1 <x<2T -1 0<x<7 -1+(-1)" 8) f(x) = { 1 sin nx 11 T<x<27 3 (9) f(x) = { sin nx 12 <x<2n (10) f(x)= -R/4 ーてくx<0 Σ 1 -1+(-1)" sin nx 0<x<A 0<x<T 37 (-1)" -1 sin nx (11) f(x) = { COS nx- 4 T T<x<2n 0<x<T s-1)" -cos nx + オーX sin nx |(12) f(x)= 0. 0<xく元 (13) f(x)= { 27-x COS nx T<x< 27
Transcribed Image Text:Exercise (3-2): find Fourier series on [0,2n] Question Answer (1) f(x) = x/2 sin nx (2) f(x)=-x 2 sin nx (3) f(x)= sin x sin x (4) f(x) = cosx COS X (5) f(x)=xsin x -1+ COS nX (6) f(x)=xcos x 2n(-1) %3D sin(nx) (n-1)(n+1) 0. 7) f(x) = 0<xくて 1 l-(-1)" sin nx 1 <x<2T -1 0<x<7 -1+(-1)" 8) f(x) = { 1 sin nx 11 T<x<27 3 (9) f(x) = { sin nx 12 <x<2n (10) f(x)= -R/4 ーてくx<0 Σ 1 -1+(-1)" sin nx 0<x<A 0<x<T 37 (-1)" -1 sin nx (11) f(x) = { COS nx- 4 T T<x<2n 0<x<T s-1)" -cos nx + オーX sin nx |(12) f(x)= 0. 0<xく元 (13) f(x)= { 27-x COS nx T<x< 27
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