+3 2C0 (aq) + Cl ag) + 20H +2 Cl0 (ag) + H20 + 2Co (aq) [C1"] When [C10) - 2.00 M, [Co*) - 0.50 M find the [OH"] necessary for E to equal -1.00 v. 1.00 M, [Co**] 3.50 M and O0.0552 O0.0316 O3. 05 x 103 0.178
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![2Co (a4)
+ Cl (ag)
+ 20H(agl
+2
+3
ci0 (aq) + H2o + 2Co (ag)
- 1.00 M, [Co*1
- 3.50 M and
[Cl")
When [C10 ]
= 0.50 M find the [OH ] necessary for E to equal -1.00 V.
= 2.00 M, [Co*1
O0.0552
O0.0316
O3. 05 x 103
0.178](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fb404b9-8e1c-41d2-a59e-964abbbd4b28%2F10c65812-6ad7-4ed2-83cf-3a884d72120e%2Fjzuieq7_processed.jpeg&w=3840&q=75)
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- Calculate the solubility of lead(II) sulfate (Ksp = 2.53x10-8) in a 0.0034 M solution of sodium sulfate. Give your answer to three sig. figs. and in exponential form (e. g. 1.23E-3).A fermenter was filled with 10L of 0.6 mol/L sodium sulfite solution containing 0.003M Cu2+ ion and the air sparger was turned on. After exactly 10 minutes, the airflow was stopped and a 5 mL sample was taken and titrated. The concentration of sodium sulfite in the sample was found to be 0.2 M. Calculate the oxygen uptakeWhich of the following are equivalent to 2,500 ppm Cu2+? (There may be more than one answer) MW: Cu (63.55) a) 2.5 ppb Cu2+ b) 2,500,000 ppb Cu c) 2.5 ppt Cu2+ d) 39.34 mM e) 0.03934 M f) 0.07868 N (in precipitation reaction) g) 0.07868 N (in redox into Cu+)
- To calculate the unknown concentration of a chemical in a solid sample, 4 different calibrationcurves were plot using 4 different methods. Which of the following method is considered asacceptable? a. Method 4, R? = 0.998b. Method 1, R2 = 0.650c. Method 2. R' = 0.890d. Method 3, R' = 0.1691) Find out the Volume (dm3) of product at STP when 0.28 M, 200 mL NaOH (aq.) reacts with 250 mL 85% H3PO4 (Sp. G.-1.067). 2) The above reaction has the product Ammonia, which when dissolved in 300 mL water makes an alkaline solution. Find its molarity (M). 3) Please re-calculate the child dose as per the BW of the baby. (Adult dose-750 mg and the BW of the baby is 50 lb (British pound) (1 lb=0.453 Kg).Which is equivalent to 2,500 ppm Cu2+?Molecular Weight: Cu (63.55) a. 0.07868 N (in precipitation reaction) b. 0.07868 N (in redox into Cu+)
- Consider the titration illustrated in Figure 8.] Anhydrous sodium carbonate (Na₂CO₃) is a primary standard. When 0.364 grams of the substance is placed in a conical flask, then 20.00 cm³ of sulphuric acid (H₂SO₄) solution is required to reach the end point of the titration. What is the concentration in mol·dm⁻³ of the sulphuric acid solution? [Give the answer to 3 decimal places. Do not type in the unit. Use a decimal point.] *This has got to be one of the worst explanations. No following at all, tried it on a problem 4 different times following the forumla and such and it sucked.Suppose you are given 0.0856ppm to be the concentration of dissolved lead found in pond water after dilution factor of 1:100 in 100ml volumetric flask and the other sample is diluted at the dilution factor of 1:2 and the concentration is 2.14ppm. How would you comment on the amount of lead in pond water
- A 10.0mL (10.0g) sample of blood was found to contain lead at a concentration of 0.5ppm. What mass of lead was contained in the blood sample? (report answer in scientific notation) Please show the breakdown of how to do the problem as I get confused when steps aren't explained. Thank you!If 500mL of 0.10M Ca2+ is mixed with 500mL of 0.10M SO42-, what mass of calcium sulfate will precipitate? Ksp for CaSO4 is 2.40 • 10-5. express answer to 3 significant figures. And include units.. At 250C, Ksp for AgBr is 5.0 x 10-13. Calculate the solubility of AgBr in g/L at 25 oC (a) in pure water; (b) In the presence of 0.2 mol L−1 NaBr solution