3 moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the pressure of water vapor in the final conditions was calculated to be 1 atm. Then, the container was changed to a constant pressure container (external pressure the gas was increased 3-fold under these conditions without any heat exchange. What is the change in the internal energy of the system. (For water vapor c = 2.01 JgK) 1 atm) and the volume of %3D %3D a. 33.54 kJ O b. -12.16 k O C.-17.35 kJ O d. -7.04 kJ e. -24.46 kJ

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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3 moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the
pressure of water vapor in the final conditions was calculated to be 1 atm. Then, the container
was changed to a constant pressure container (external pressure
the gas was increased 3-fold under these conditions without any heat exchange. What is the
1 atm) and the volume of
%3D
change in the internal energy of the system.
(For water vapor c =
2.01 Jg K)
O a. 33.54 kJ
O b. -12.16 kJ
O C. -17.35 kJ
O d. -7.04 kJ
e. -24.46 kJ
Transcribed Image Text:3 moles of water vapor at 110 °C was heated to 140 °C in a constant volume container, and the pressure of water vapor in the final conditions was calculated to be 1 atm. Then, the container was changed to a constant pressure container (external pressure the gas was increased 3-fold under these conditions without any heat exchange. What is the 1 atm) and the volume of %3D change in the internal energy of the system. (For water vapor c = 2.01 Jg K) O a. 33.54 kJ O b. -12.16 kJ O C. -17.35 kJ O d. -7.04 kJ e. -24.46 kJ
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