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- (Program) Write a program that tests the effectiveness of the rand() library function. Start by initializing 10 counters, such as zerocount, onecount, twocount, and so forth, to 0. Then generate a large number of pseudorandom integers between 0 and 9. Each time 0 occurs, increment zerocount; when 1 occurs, increment onecount; and so on. Finally, display the number of 0s, 1s, 2s, and so on that occurred and the percentage of time they occurred.We have to create a program in java in which the below mentioned things should be there- You have been given the head to a singly linked list of integers. Write a function check to whetherthe list given is a 'Palindrome' or not.Input Format:Elements of linked listOutput Format:True or FalseSample Input 1:9 3 2 2 3 9Sample Output 1:trueSample Input 2:0 2 3 2 5Sample Output 2:falseWrite programs with these input and output Given positive integers m and n, find the number of ontofunctions from a set with m elements to a set with n elements.
- Implement the FindText() function, which has two strings as parameters. The first parameter is the text to be found in the user provided sample text, and the second parameter is the user provided sample text. The function returns the number of instances a word or phrase is found in the string. In the PrintMenu() function, prompt the user for a word or phrase to be found and then call FindText() in the PrintMenu() function. Before the prompt, call cin.ignore() to allow the user to input a new string.Ex: Enter a word or phrase to be found: more "more" instances: 5Given the following function, what happens if a[] contains just one element that doesn't match val? int binarySearch(int a[], int first, int last, int val){ if (first > last) return -1; int middle = (first + last) / 2; if (a[middle] == val) return middle; if (a[middle] < val) return binarySearch(a, middle+1, last, val); else return binarySearch(a, first, middle-1, val);} Group of answer choices binarySearch never calls itself again and terminates (recursion never happens) binarySearch calls itself once then terminates (recursion happens once) binarySearch calls itself twice then terminates (recursion happens twice) binarySearch calls itself 3 times then terminates (recursion happens 3 times)I have to implement a SubstringGenerator (class) that generates all substrings of a string recursively. For example, the substrings of the string “rum” are the seven strings “rum”, “ru”, “r”, “um”, “u”, “m”, “” Hint: First enumerate all substrings that start with the first character. There are n of them if the string has length n. Then enumerate the substrings of the string that you obtain by removing the first character. Here is what your output should look like after your project is completed. (The order of your substrings is not important, if your generator produces all substrings correctly). Substrings of "ab" Actual: '' 'b' 'a' 'ab' Expected: '' 'b' 'a' 'ab' Substrings of "abc" Actual: '' 'c' 'b' 'bc' 'a' 'ab' 'abc' Expected: '' 'c' 'b' 'bc' 'a' 'ab' 'abc' Substrings of "abc123" Actual: '' '3' '2' '23' '1' '12' '123' 'c' 'c1' 'c12' 'c123' 'b' 'bc' 'bc1' 'bc12' 'bc123' 'a' 'ab' 'abc' 'abc1' 'abc12' 'abc123' Expected: '' '3' '2' '23' '1' '12' '123' 'c' 'c1'…
- Implement the Plates class buildMap function so that it populates the HashMap with the state abbreviations as keys and the counts of how many each appear in the file as values. Sometimes, the parking attendant will add special notation to help her remember something about a specific entry. There are just non alphabetic characters that she adds to the state - your program should ignore these characters so that an entry like NY* still counts toward the NY plate count. She is also very inconsistent with how she enters the plates. Sometimes she uses upper case, sometimes lowercase, and sometimes she even uses a mix. Be sure to account for this in your program. Only add information for plates in New England (Maine, New Hampshire, Vermont, Massachusetts, Rhode Island, and Connecticut). Plates.java import java.util.Arrays; import java.util.HashMap; import java.util.HashSet; import java.util.Map; import java.util.Set; public class Plates { private Map<String, Integer> plateMap;…In this question, we are going to write a Racket functionwordMaxIndex that calculates the maximum index of each word thatappears in an input word list. For example, if the input is’(time is long but life is short)Then one output can be((time 0) (long 2) (but 3) (life 4) (is 5) (short 6))The index of the first word in a word list is 0; the index for the secondword is 1; etc. Therefore, in the previous example, the maximum indexfor word “time” is 0; the maximum index for word “is” is 5, since “is”appears twice, at index 1 and 5. Note that you are not asked to sortthe words in the output. Therefore, the output is correct as long asthe indexes are correct.Do the following steps to implement the word-index program. In ourdiscussion, we call a word with an index a word-index pair, for example,(short 6) and (is 5) are word-index pairs. We call a list of word-index pairs a word-index list.(a) Write a function initialWIList that takes a list ofwords and creates a word-index list. The resulting…Write a program that lists all ways people can line up for a photo (all permutations of a list of strings). The program will read a list of one word names (until -1), and use a recursive method to create and output all possible orderings of those names, one ordering per line. When the input is: Julia Lucas Mia -1 then the output is (must match the below ordering): Julia Lucas Mia Julia Mia Lucas Lucas Julia Mia Lucas Mia Julia Mia Julia Lucas Mia Lucas Julia partial code below, only lines 9-11, and 18 can be added onto, the rest must stay the same. #include <vector>#include <string>#include <iostream> using namespace std; // TODO: Write method to create and output all permutations of the list of names.void AllPermutations(const vector<string> &permList, const vector<string> &nameList) { } int main(int argc, char* argv[]) { vector<string> nameList; vector<string> permList; string name; // TODO: Read in a list of names; stop…
- Implement the following function, without using any data structure. /* Given two vectors of chars, check if the two vectors are permutations of each other, i.e., they contains same values, in same or different order.e.g., V1=[‘a’,’b’,’a’] and V2=[‘b’,’a’,’a’] stores same multi-set of data points: i.e., both contains two ‘a’, and one ‘b’. e.g., V3=[‘a’,’c’,’t’,’a’] and V4=[‘a’,’c’,’t’] are not same multi-set. V3 contains two ‘a’s, while V4 has only one ‘a’. Note: when considering multiset, the number of occurrences matters. @param list1, list2: two vectors of chars @pre: list1, list2 have been initialized @post: return true if list1 and list2 stores same values (in same or different order); return false, if not. */ bool SameMultiSet (vector<char> list1, vector<char> list2)Please help. How to solve this on Java language by using only Dynamic Programming? Thank you. We are given a set A of integers. Check whether we can partition A into three subsets with equal sums. It is important to note that all elements should be included in the equally divided subsets; no element should be left out, and none of the elements should be repeated in the subsets.For example: A={4,7,6,2,10,7,10,2} has such a partition: {4,2,10}, {7,7,2},{6,10}Input: A set, A, of integersOutput: if we can partition A into three subsets with equal sums, print subsets otherwise present a suitable message.The goal is to rewrite the function, below, such that passes in a different list of parameters, particularly eliminating the need to pass low and high for each recursive call to binary_search. defbinary_search(nums,low,high,item): mid=(low+high)//2iflow>high:returnFalse #The item doesn't exist in the list!elifnums[mid]==item:returnTrue# The item exists in the list!elifitem<nums[mid]:returnbinary_search(nums,low,mid-1,item)else:returnbinary_search(nums,mid+1,high,item) The new function should be prototyped below. The number of changes between the given version, and the one requested is not significant. defbinary_search(nums,item):pass# Remove this and fill in with your code Tip: If you consider that high and low are used to create a smaller version of our problem to be processed recursively, the version requested will do the same thing, just through a different, more Pythonic technique.