3.1524 g HCI (FW 36.46) was diluted with 45 mL water and titrated with 1.0149 M NAOH (FW 40) using methyl red as indicator. 28.02 mL of NaOH was required to neutralize the HCI. Calculate the percentage w/w of HCI. Record your answer in decimal notation to 2 decimal places. Answer = % w/w

3.1524 g HCI (FW 36.46) was diluted with 45 mL water and titrated with 1.0149 M NAOH (FW 40) using methyl red as indicator. 28.02 mL of NaOH was required to neutralize the HCI. Calculate the percentage w/w of HCI. Record your answer in decimal notation to 2 decimal places. Answer = % w/w

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.16QAP

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Concept explainers

Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

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3.1524 g HCI (FW 36.46) was diluted with 45 mL water and titrated with 1.0149 M NAOH (FW 40) using methyl red as indicator. 28.02 mL of NAOH was
required to neutralize the HCI. Calculate the percentage w/w of HC. Record your answer in decimal notation to 2 decimal places.
Answer =
% w/w
%3D

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