324 out of a simple random sample of 400 students hated their online math course. a) Find a 99% confidence interval for the true proportion of students who liked their online math course. b) Will this interval allow us to conclude that fewer than 85% of all students hated their online math course? Explain.

Q: Construct the 99% confidence interval estimate of the population proportion p if the sample size is…

A: Obtain the 99% confidence interval estimate of the population proportion. The 99% confidence…

Q: 5. In a random sample of 400 college students, 16 had perfect attendance Find the 95% confidence…

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

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Q: A university dean is interested in determining the proportion of students who receive some sort of…

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Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

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Q: In a survey of 3005 adults aged 57 through 85 years, it was found that 81.7% of them used at least…

A: Given :  n = 3005 p̂=0.817

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: In a recent poll, 430 people were asked if they liked dogs, and 41% said they did. Find the margin…

A: It is given that the value of n is 430, p hat is 0.41 and the confidence level is 0.99.

Q: Of 41 bank customers depositing a check, 22 received some cash back. Construct a 90% confidence…

A:

Q: 10 Life insurance policies in a sample of 200 taken out of 50,000 were found to be insured for less…

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Q: To determine the preference in the consumption of dairy products in a residential area, a survey is…

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Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: Suppose I wanted to know the proportion of students who are paying attention in class, so I give a…

A: Confidence Interval for Proportion A confidence interval is a statistical method that denotes a…

Q: Find the 68% confidence interval for the percentage of leaky diapers with a sample of 100 diapers…

A: Let X be the number of defective diapers and n is the number of diapers. From the given information,…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

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Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: It is given that the number of US adults is 2255, among them 1787 are uses the internet regularly.…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community…

A: Given that, Out Of 380 randomly selected medical students, 21 said that they planned to work in a…

Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: 9. The Centers for Disease Control and Prevention reported a survey of randomly selected Americans…

A:

Q: when 282 college students are randomly selected and surveyed, it is found that 109 own a car. find a…

A: It is given that sample size (n) is 282 and x is 109.

Q: In a Harvard School of Public Health survey, 2105 of 10,904 randomly selected U.S. college students…

A: Given data is appropriate for testing of hypothesis. Because it is a large sample test for single…

Q: consider  a random sample of 300 students in a university,75 of them declared that they like playing…

A:

Q: Of 380 randomly selected medical students, 210 said that they planned to work in a rural community.…

A: Solution: Let X be the number of medical students said that they planned to work in a rural…

Q: In a survey of 3393 adults aged 57 through 85​ years, it was found that 82.8​% of them used at least…

A: (a). Obtain the number of subjects who used at least one prescription medicine: It is given that…

Q: In a survey of 1000 randomly selected adults in the US, participants were asked what their most…

A:

Q: Ten engineering schools in the United States were surveyed. The sample contained 250 electrical…

A: Given that  n1=250 , X1=80 , n2=175 , X2=40

Q: In a random sample of 532 individuals, 78% stated they needed a laptop in order to work from home.…

A: Given that  n=532 , p=78%=0.78 99% confidence level

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given that, X = 118 N = 200 99% confidence level

Q: If n=490 and ˆpp^ (p-hat) =0.46, find the margin of error at a 99% confidence level.Give your answer…

A:

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: A university planner wants to determine the proportion of undergraduate students who plan to attend…

A:

Q: construct a 95% confidence interval for the true proportion of the population having banking…

A: It ia given that Sample size n = 100 Number of persons having banking relations with either the…

Q: A survey of 100 students showed that 20 % of them planned to major in business. What is a 95 %…

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Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

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Q: After an advertisement campaign of polish, the manufacturers wanted to know how many of the possible…

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Q: university dean is interested in determining the proportion of students who receive some sort of…

A:

Q: consider a random sample of 300 students in a university, 75 of them declared that they like playing…

A: A random sample of 300 students in a university in which 75 of them declared that they like playing…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: (a) From the Standard Normal Table, the z value for 99% level is 2.576. The sample proportion is,…

Q: 2. Solve for the margin of error for a 98% confidence level, the sample size is 1230, of which 40%…

A: 2)GivenConfidence level =98%sample size(n)=1230p^=0.40

Q: 7) 324 out of a simple random sample of 400 students hated their online math course. a) Find a 99%…

A:

Q: When 500 college students were surveyed, 30% said that they own their car. Construct a 95%…

A: Here we want to find the 95% confidence interval.

Q: 2. A sample of 430 business applications included 150 men. Find the 99% confidence interval of the…

A: Answer:-  Given,  X=150 n=430

Q: 2) Suppose a college is planning to hold an event for students. In the survey of 130 on-campus…

A:

Q: Of 375 randomly selected students, 30 said that they planned to work in a rural community. Find 95%…

A: Using z ditribution to construct the interval.

Q: (b) A sample of 1200 network engineer job applications included 720 are from expatriates. Find  the…

A:

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…

Q: In a survey of 2273 ​adults, 728 say they believe in UFOs.   Construct a 99% confidence interval for…

A: Given Information: Sample size (n) = 2273 Out of which X = 728 adults say they believe in UFOs. To…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.