4- A 4KVA, 200/400V, 50HZ, single phase transformer gave the following test figures: No-load (low-voltage data): 200V, 0.7A and 60W. Short-circuit (high voltage data): 9V, 6A and 21.6W. Calculate: a- The magnetizing current and the component corresponding to iron loss at normal voltage and frequency. b- The efficiency on full load at unity power factor. c- The secondary terminal voltage on full load at power of unity, 0.8 lagging and 0.8 leading. [a/ 0.63A, 0.3A; b/97.100%; c/ 394V, 387V, 403.4V]

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter3: Power Transformers
Section: Chapter Questions
Problem 3.9P
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4- A 4KVA, 200/400V, 50HZ, single phase transformer gave the following test figures:
No-load (low-voltage data): 200V, 0.7A and 60W.
Short-circuit (high voltage data): 9V, 6A and 21.6W.
Calculate:
a- The magnetizing current and the component corresponding to iron loss at normal
voltage and frequency.
b- The efficiency on full load at unity power factor.
c- The secondary terminal voltage on full load at power of unity, 0.8 lagging and 0.8
leading. [a/ 0.63A, 0.3A; b/97.100%; c/ 394V, 387V, 403.4V]
Transcribed Image Text:4- A 4KVA, 200/400V, 50HZ, single phase transformer gave the following test figures: No-load (low-voltage data): 200V, 0.7A and 60W. Short-circuit (high voltage data): 9V, 6A and 21.6W. Calculate: a- The magnetizing current and the component corresponding to iron loss at normal voltage and frequency. b- The efficiency on full load at unity power factor. c- The secondary terminal voltage on full load at power of unity, 0.8 lagging and 0.8 leading. [a/ 0.63A, 0.3A; b/97.100%; c/ 394V, 387V, 403.4V]
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