Need 2 different variations answers and with explanation please. Thank you. PART 4: Using the custom circuits you built in Parts 1-3, built a 4 bit 2's Complement multiplier that usesthe inversion method discussed in class.HINTS: INVERSION METHOD:1) If input A is negative, invert it. If input A is positive, leave it alone.2) If input B is negative, invert it. If input B is positive, leave it alone.3) Multiply A and B.4) If both A and B originally had the same sign (both positive or both negative), do nothing.5) If A and B originally had different signs (one was positive, the other negative), invert the product. 4 bit 2's Complement MultiplierINPUT A: 4 bit 2's Complement numberINPUT B: 4 bit 2's Complement numberOUTPUT: the product of A x B represented as a 8 bit 2's Complement numberYou are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gatesto build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim built in circuits.Each custom circuit is to be implemented as a sub-circuit.PART 1: Build a 4 bit controlled 2's Complement InverterPART 2: Build a 8 bit controlled 2's Complement InverterPART 3: Build a 4 Bit UNSIGNED MultiplierA: 4 Bit InputB: 4 Bit InputMultiplier0000 000O

4 bit 2's Complement Multiplier INPUT A: 4 bit 2's Complement number INPUT B: 4 bit 2's Complement number OUTPUT: the product of A x B represented as a 8 bit 2's Complement number You are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gates to build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim built in circuits. Each custom circuit is to be implemented as a sub-circuit. PART 1: Build a 4 bit controlled 2's Complement Inverter PART 2: Build a 8 bit controlled 2's Complement Inverter PART 3: Build a 4 Bit UNSIGNED Multiplier A: 4 Bit Input B: 4 Bit Input Multiplier 0o00000o

4 bit 2's Complement Multiplier INPUT A: 4 bit 2's Complement number INPUT B: 4 bit 2's Complement number OUTPUT: the product of A x B represented as a 8 bit 2's Complement number You are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gates to build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim built in circuits. Each custom circuit is to be implemented as a sub-circuit. PART 1: Build a 4 bit controlled 2's Complement Inverter PART 2: Build a 8 bit controlled 2's Complement Inverter PART 3: Build a 4 Bit UNSIGNED Multiplier A: 4 Bit Input B: 4 Bit Input Multiplier 0o00000o

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 9VE

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4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement numberINPUT B: 4 bit 2’s Complement numberOUTPUT: the product of A x B represented as a 8 bit 2’s Complement number You are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gates to build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim’s built in circuits. Each custom circuit is to be implemented as a sub-circuit as discussed in class. PART 1: Build a 4 bit controlled 2’s Complement Inverter as a subcircuit named 4BitInverter PART 2: Build a 8 bit controlled 2’s Complement Inverter as a subcircuit named 8BitInverter PART 3: Build a 4 Bit UNSIGNED Multiplier as a subcircuit named UnsignedMultiplier PART 4: Using the 3 subcircuits you built in Parts 1-3, built a 4 bit 2’s Complement multiplier that uses the inversion method discussed in class. Name this circuit: SignedMultiplier HINTS: INVERSION METHOD: 1) If input A is negative, invert it. If input A is…
4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement number INPUT B: 4 bit 2’s Complement number OUTPUT: the product of A x B represented as a 8 bit 2’s Complement number You are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gates to build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim’s built in circuits. Each custom circuit is to be implemented as a sub-circuit as discussed in class. PART 4: Using the 3 subcircuits you built in Parts 1-3, built a 4 bit 2’s Complement multiplier that uses the inversion method discussed in class. Name this circuit: SignedMultiplier HINTS: INVERSION METHOD: 1) If input A is negative, invert it. If input A is positive, leave it alone. 2) If input B is negative, invert it. If input B is positive, leave it alone. 3) Multiply A and B. 4) If both A and B originally had the same sign (both positive or both negative), do nothing. 5) If A and B originally had different signs…
4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement number INPUT B: 4 bit 2’s Complement number OUTPUT: the product of A x B represented as a 8 bit 2’s Complement number You are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gates to build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim’s built in circuits. Each custom circuit is to be implemented as a sub-circuit as discussed in class. PART 1: Build a 4 bit controlled 2’s Complement Inverter as a subcircuit named 4BitInverter PART 2: Build a 8 bit controlled 2’s Complement Inverter as a subcircuit named 8BitInverter PART 3: Build a 4 Bit UNSIGNED Multiplier as a subcircuit named UnsignedMultiplier PART 4: Using the 3 subcircuits you built in Parts 1-3, built a 4 bit 2’s Complement multiplier that uses the inversion method discussed in class. Name this circuit: SignedMultiplier HINTS: INVERSION METHOD: 1) If input A is negative, invert it. If input A…
4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement number INPUT B: 4 bit 2’s Complement number OUTPUT: the product of A x B represented as a 8 bit 2’s Complement number You are only allowed to use the basic gates: NOT, AND, OR, XOR. You may however, use these basic gates to build your own custom circuits (i.e. Adder). You are NOT ALLOWED to use Logisim’s built in circuits. Each custom circuit is to be implemented as a sub-circuit as discussed in class. PART 1: Build a 4 bit controlled 2’s Complement Inverter as a subcircuit named 4BitInverter
4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement numberINPUT B: 4 bit 2’s Complement numberOUTPUT: the product of A x B represented as a 8 bit 2’s Complement number Do this:Build a 4 Bit UNSIGNED Multiplier as a subcircuit named UnsignedMultiplier use AND gate ,full and half adders for the circuit
Build a circuit that takes four bits as input: W, X, Y, Z. Treat WX as a 2-bit unsigned binary number, and treat YZ as a second 2-bit unsigned binary number. Your circuit should generate the output corresponding to the product of WX and YZ. You will need 4 bits of output for this problem.For example, if your input was 1011, your inputs correspond to 2 and 3. That product is 6, so your output will be 0110.Create a truth table for this problem, show all k-maps and minimizations, and build the corresponding (minimized) circuit. Use XOR, XNOR, NAND, and NOR as appropriate if it reduces the number of gates used.
4 bit 2’s Complement Multiplier INPUT A: 4 bit 2’s Complement number INPUT B: 4 bit 2’s Complement number OUTPUT: the product of A x B represented as a 8 bit 2’s Complement number PART 3: Build a 4 Bit UNSIGNED Multiplier as a subcircuit named UnsignedMultiplier use AND gate ,full and half adders for the circuit
Design a circuit that has two inputs X, and S, where X represents an 8-bit BCD number, S is a sign bit. The circuit has one output Y, which is the Binary representation of the signed-magnitude BCD number. A negative output is represented in the Binary 2’s- complement form. You need to think of two design alternatives. Submission guidelines: 1. You should write a report that at least contains the following sections: 1. Problem definition. 2. Design alternatives : 2.1. Alternative 1 block diagram 2.2. Alternative 2 block diagram 3. Design selection criteria 4. Detailed circuit design of the selected alternative. 5. Verilog modules, and simulation results for all modules, and for the whole circuit of the selected alternative .
Design a circuit that takes three bits, X2, X1, X0 as input and produces one output, F. F is 1 if and only if 2<=X<=5 when X = (X2, X1, X0) is read as an unsigned integer. For example, if X2=1, X1=0, and X0=0, then the unsigned binary value is 100, which is 4, so the output would be 1. Your Assignment For This Problem Includes the Following Design the necessary circuit using Logisim to implement the situation described above. Use Kmaps for simplification. Be VERY careful to get the correct functions for your output before simplifying and designing the circuit with Logisim. You should minimize the circuit. Your circuit should have three inputs and one LED output. All inputs (X2, X1, X0) and output (F) should be labeled (in Logisim, not by hand). Please use these names to indicate the inputs and output so all projects are consistent. You should also include your name as a label on the circuit. Test your circuit to be sure it is working correctly.
In this problem, you should design a two-bit comparator. This circuit should have three outputs named l, g, and eq. The circuit should get two digits binary numbers (00, 01, 10, 11), and the output should change based on these rules:• If first number > second number then g = 1, l = 0, and eq = 0• If first number < second number then g = 0, l = 1, and eq = 0• If first number = second number then g = 0, l = 0, and eq = 1Your circuit will have 4 input (2 bit for the first number, and 2 bits for the second number)a. Draw the truth table for the comparator for unsigned numbers b. Show the circuit.
The Excess-3 coding system is a four-bit digital coding system for encoding all decimal digits from 0 to 9. To encode a decimal digit, we add three to it and then convert the result to binary. A valid code has the following range:1. Minimum = 0011, encoding decimal 0( 0 + 3 = 3 = 0011)2. Maximum = 1100, encoding decimal 9(9 + 3 =12 = 1100)Design a logic circuit that will detect an error if a four-bit number is not a valid Excess-3 number. (Hint: Use four input variables to represent the four bits of the Excess_3 number. If the combination of the input bits is 0000,0001,0010,1101,1110, or 1111, the output will be HIGH. For all other cases, the output will be LOW.)
Consider two four bit numbers A and B, where either both the numbers are even or both of them are odd. Construct a combinational circuit which will perform the following operations: If A and B are both even, calculate A+B, else calculate A-B