4. In an experiment to investigate the performance of four different brands of spark plugs intended for use on a 125-cc two-stroke motorcycle, five plugs of each brand were tested and the number of miles (at a constant speed) until failure was observed. The partial ANOVA table for the data appears below. degrees of freedom Sum of Mean Source squares square Fyalue Brand Error 14,713.69 Total 310,500.76
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- 2) The table to the right shows the cost per ounce (in dollars) for a random sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal. At α=0.025, can you conclude that the mean costs per ounce are different? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn from a normal population, that the samples are independent of each other, and that the populations have the same variances. Very good stain removal Good stain removal Fair stain removal 0.37 0.58 0.34 0.51 2.74 1.25 0.33 0.98 0.44 1.47 0.42 0.49 0.46 0.48 1.31 (a) Identify the claim and state H0 and Ha. Choose the correct answer below. A. H0: μ1=μ2=μ3=μ4=μ5=μ6 Ha: At least two means are different from the others. (claim) B. H0: At least one mean is different from the others. (claim) Ha: μ1=μ2=μ3=μ4=μ5=μ6 C. H0: μ1=μ2=μ3 Ha:…According to a certain government agency for a large country, the proportion of fatal traffic accidents in the country in which the driver had a positive blood alcohol concentration (BAC) is 0.36. Suppose a random sample of 110 traffic fatalities in a certain region results in 49 that involved a positive BAC. Does the sample evidence suggest that the region has a higher proportion of traffic fatalities involving a positive BAC than the country at the α=0.05 level of significance?A major credit card company is interested in the proportion of individuals who use a competitor’s credit card. Their null hypothesis is H0: p=0.65H0: p=0.65, and based on a sample they find a sample proportion of 0.70 and a pp-value of 0.053. Is there convincing statistical evidence at the 0.05 level of significance that the true proportion of individuals who use the competitor’s card is actually greater than 0.65 ?
- A company surveyed adult Americans about their consumer debt. The article reported that 48% of millennials (those born between 1980 and 1996) and 62% of Gen Xers (those born between 1965 and 1971) did not pay off their credit cards each month, and therefore carried a balance from month to month. Suppose that these percentages were based on representative samples of 450 millennials and 300 Gen Xers. Is there convincing evidence that the proportion of Gen Xers who do not pay off their credit cards each month is greater than this proportion for millennials? Test the appropriate hypotheses using a significance level of 0.05. (Let p1 be the proportion of Gen Xers who do not pay off their credit cards each month, and p2 be the proportion of Millennials who do not pay off their credit cards each month.) State the appropriate null and alternative hypotheses. H0: p1 − p2 = 0 Ha: p1 − p2 ≠ 0 H0: p1 − p2 > 0 Ha: p1 − p2 < 0 H0: p1 − p2 < 0 Ha: p1 − p2 > 0 H0: p1 − p2 = 0…A company surveyed adult Americans about their consumer debt. The article reported that 48% of millennials (those born between 1980 and 1996) and 62% of Gen Xers (those born between 1965 and 1971) did not pay off their credit cards each month, and therefore carried a balance from month to month. Suppose that these percentages were based on representative samples of 450 millennials and 300 Gen Xers. Is there convincing evidence that the proportion of Gen Xers who do not pay off their credit cards each month is greater than this proportion for millennials? Test the appropriate hypotheses using a significance level of 0.05. (Let p1 be the proportion of Gen Xers who do not pay off their credit cards each month, and p2 be the proportion of Millennials who do not pay off their credit cards each month.) State the appropriate null and alternative hypotheses. H0: p1 − p2 = 0 Ha: p1 − p2 > 0 H0: p1 − p2 = 0 Ha: p1 − p2 < 0 H0: p1 − p2 > 0 Ha: p1 − p2 < 0 H0: p1 − p2 <…