4000 100 80 60 8 8 40 IR Spectrum (liquid film) 20 % of base peak 3000 59 2000 115 87 11 80 40 13C NMR Spectrum (500 MHz. CDCI, solution) DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 1 10 9 8 1737 v (cm') M** 146 120 160 m/e 160 1600 7 wy 1200 6 120 800 Mass Spectrum 200 240 280 C6H1004 solvent 80 5 4 1 Problem 46 No significant UV absorption above 220 nm L 40 3 2 0 1 8 (ppm) TMS L 0 8 (ppm) 135

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass in this example
4000
100
80
60
40
IR Spectrum
(liquid film)
20
% of base peak
3000
59
2000
115
87
id
80
40
13C NMR Spectrum
(500 MHz. CDCI, solution)
DEPT CH₂ CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
8
10
9
1737
v (cm')
M**
146
120 160
m/e
160
1600
7
jez
1200
6
200 240
120
800
Mass Spectrum
C6H1004
280
solvent
I
80
5 4
1
Problem 46
No significant UV
absorption above 220 nm
L
40
3
2
08 (ppm)
TMS
L
1
0
8 (ppm)
135
Transcribed Image Text:4000 100 80 60 40 IR Spectrum (liquid film) 20 % of base peak 3000 59 2000 115 87 id 80 40 13C NMR Spectrum (500 MHz. CDCI, solution) DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 8 10 9 1737 v (cm') M** 146 120 160 m/e 160 1600 7 jez 1200 6 200 240 120 800 Mass Spectrum C6H1004 280 solvent I 80 5 4 1 Problem 46 No significant UV absorption above 220 nm L 40 3 2 08 (ppm) TMS L 1 0 8 (ppm) 135
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