D m) o)x4 mol H2O/5 mol 0)=.25mol Hz013125mol 0 2mal C0/Smol Oz.175 moñ9tCalculate the mass of each product that isby calculation which reuctant is the LimitingSuppose Oa of euch reactant is taken Show47) Foreach of theolowing unbalanced equation,expectint.A.CCo2187 5pmol x44.019lmal=8.25199)Imass of HeO prodcuied6. Alis)+ Clziq) > AIGlziss=4.5025gNes of AICI3 produced =.094mol x133.344 Imol 12.52C. NaOHIS) + COz(4) → Na COgs) + HzO12)(25 mol NaOH)x[Imol Na,CO,/2mol NaOH)=.125 mol Na_Cesmuss of Na,0g produad =125meli45.49888glmol = 13.28g4.25mot NaOH)x(1 ml HzO/2ml NalH) =.125mol HzOof!!D. NatHcOs65) + HGlcag) > NaCleag) + HeOll) +

Given balanced reaction, NaHCO3(s) + HCl(aq) → NaCl(aq) + H2O(l) + CO2(g) Mass of each reactant…

47) For each of the fallowing unbalanccel equation, by calculation which, reactant is the Limiting Suppose Oa of euch reactant is taken Show. Calculate Hthe mass of each product that is expe nt Co2 187 5ynol x44.01a Imal= 1875 mol CO Imass of HeO produced 8.25199 B. Alis)+ Clzla)> AIGl3iss naole of A-(10u 12685a/mol)=.3706mul %3D =4.5025g %3D 1410 mol mosso of AICI, produced = .094mol x133.34g/mol /2.5340g C. NaOH(s) + COz(4) → Na COgs) + H2O12) (.25 mol NaOH)x[lmol_Na,CO3/2mol NAOH)=.12S mol Na,coz muss of Na,0, prduced =125motiWS.4888glmol = 13.2486g 4,25 mot NaOH)x (I mel HzO/2ml NallH)=125mol HzO of pradlucecd E,125 mul = 2. D. NatHCO 6s) + HGlcug) → NaClyag) + Hez011) +

47) For each of the fallowing unbalanccel equation, by calculation which, reactant is the Limiting Suppose Oa of euch reactant is taken Show. Calculate Hthe mass of each product that is expe nt Co2 187 5ynol x44.01a Imal= 1875 mol CO Imass of HeO produced 8.25199 B. Alis)+ Clzla)> AIGl3iss naole of A-(10u 12685a/mol)=.3706mul %3D =4.5025g %3D 1410 mol mosso of AICI, produced = .094mol x133.34g/mol /2.5340g C. NaOH(s) + COz(4) → Na COgs) + H2O12) (.25 mol NaOH)x[lmol_Na,CO3/2mol NAOH)=.12S mol Na,coz muss of Na,0, prduced =125motiWS.4888glmol = 13.2486g 4,25 mot NaOH)x (I mel HzO/2ml NallH)=125mol HzO of pradlucecd E,125 mul = 2. D. NatHCO 6s) + HGlcug) → NaClyag) + Hez011) +

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 100CP: he production capacity for acrylonitrile (C3H3N)in the United States is over 2 billion pounds per...

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