5- A chemist is given a nonelectrolyte white powder for analysis. 38.7 g of this substance is dissolved in 100.0 g of water. It is determined that the resulting solution freezes at -4.0°C. Additionally, the elemental composition of the substance is identified and found to be 40.0% C, 6.7% H and 53.3 % O by mass. Find the molecular formula of this unknown white powder using these experimental evidences (Kt of water: 1.86°C/m, C: 12 g/mol, H: 1 g/mol, O: 16 g/mol).
5- A chemist is given a nonelectrolyte white powder for analysis. 38.7 g of this substance is dissolved in 100.0 g of water. It is determined that the resulting solution freezes at -4.0°C. Additionally, the elemental composition of the substance is identified and found to be 40.0% C, 6.7% H and 53.3 % O by mass. Find the molecular formula of this unknown white powder using these experimental evidences (Kt of water: 1.86°C/m, C: 12 g/mol, H: 1 g/mol, O: 16 g/mol).
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.99QE
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5- A chemist is given a nonelectrolyte white powder for analysis. 38.7 g of this substance is
dissolved in 100.0 g of water. It is determined that the resulting solution freezes at -4.0°C.
Additionally, the elemental composition of the substance is identified and found to be 40.0%
C, 6.7% H and 53.3 % O by mass. Find the molecular formula of this unknown white powder
using these experimental evidences (Kt of water: 1.86°C/m, C: 12 g/mol, H: 1 g/mol, O: 16
g/mol).
6- The following reaction takes place into a constant-volume flask at 427°C:
CCL(g) = C(s) +2 Cl:(g)
AH=132 kJ
At 427°C, the equilibrium constant for the reaction given above is K. = 1.3×10-. A flask is
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