solve in python 5. Convert the following recursive functions into iterative functions.def max(k, n):if k == []: return nelif k[0] > n: return max(k[1:], k[0])else: return max(k[1:], n)def sum_odd(n, total):if nelif n % 2 == 0: return sum_odd(n - 1, total)else: return sum_odd(n - 2, total + n)1: return total==Hint: You may find it necessary to reduce the number of parameters for the iterative version.

Here we have given 2 functions, max() and sum_odd(). The function max() returns the largest value…

5. Convert the following recursive functions into iterative functions. def max(k, n): if k == []: return n elif k[0] > n: return max(k[1:], k[0]) else: return max(k[1:], n) def sum_odd(n, total): if n == 1: return total elif n % 2 == 0: return sum_odd(n 1, total) else: return sum_odd(n - 2, total + n) Hint: You may find it necessary to reduce the number of parameters for the iterative version.

5. Convert the following recursive functions into iterative functions. def max(k, n): if k == []: return n elif k[0] > n: return max(k[1:], k[0]) else: return max(k[1:], n) def sum_odd(n, total): if n == 1: return total elif n % 2 == 0: return sum_odd(n 1, total) else: return sum_odd(n - 2, total + n) Hint: You may find it necessary to reduce the number of parameters for the iterative version.

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 8SA

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