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- Help with Part A B and C: Ksp Values: Ionic CompoundFormulaKsp Aluminum hydroxideAl(OH)31.8×10–5 Aluminum phosphateAlPO46.3×10–19 Barium carbonateBaCO35.1×10–9 Barium chromateBaCrO41.2×10–10 Barium fluorideBaF21.0×10–6 Barium hydroxideBa(OH)25×10–3 Barium sulfateBaSO41.1×10–10 Barium sulfiteBaSO38×10–7 Barium thiosulfateBaS2O31.6×10–6 Bismuthyl chlorideBiOCl1.8×10–31 Bismuthyl hydroxideBiOOH4×10–10 Cadmium carbonateCdCO35.2×10–12 Cadmium hydroxideCd(OH)22.5×10–14 Cadmium oxalateCdC2O41.5×10–8 Cadmium sulfide*CdS8×10–28 Calcium carbonateCaCO32.8×10–9 Calcium chromateCaCrO47.1×10–4 Calcium fluorideCaF25.3×10–9 Calcium hydrogen phosphateCaHPO41×10–7 Calcium hydroxideCa(OH)25.5×10–6 Calcium oxalateCaC2O42.7×10–9 Calcium phosphateCa3(PO4)22.0×10–29 Calcium sulfateCaSO49.1×10–6 Calcium sulfiteCaSO36.8×10–8 Chromium(II) hydroxideCr(OH)22×10–16 Chromium(III) hydroxideCr(OH)36.3×10–31 Cobalt(II) carbonateCoCO31.4×10–13 Cobalt(II) hydroxideCo(OH)21.6×10–15 Cobalt(III) hydroxideCo(OH)31.6×10–44…For each of the answers in Problem 60, state whether the species is polar or nonpolar.How do you explain the pattern/trend in the distance between the anion of an acid and H3O+? The acid strength is HCl > HNO3 > HF > HOCl, but I don't understand why the lengths vary like this. Or does it have to do with electronegativity? If it does have to do with electronegativity, why doesn't HF have the shortest length? Or is it because OCl- is more elctronegatvie than F-? Also, does an acid's strength decrease/increase with increasing electronegativity of its conjugate base? When looking at the trend, HI is stronger than HBr, which is stronger than HCl. However, HClO4 is stronger than all of these acids, which I don't understand why.
- Excessive nutrients dumped into waterways can create “algae blooms” that rapidly consume all of the dissolved O2 and trigger production of enough H2S to create “dead zones” like the ones that exist off the coast of Denmark and in the Gulf of Mexico immediately south of the Mississippi River delta. a. Since Group 16 element substitution is a recurring theme in that Group’s chemistry –e.g., oxygen substituting for Se and Te in the production of H2Se and H2Te, respectively –maybe molecular oxygen (O2) could be bubbled into these dead zones and react with the H2S.Write out a balanced chemical equation for the reaction between H2S and O2 to form elemental sulfur (S8) as a product that would precipitate out. b. Using bond dissociation energies, calculate if this reaction would be thermodynamically favorable. c. If your answer to part (b) is “yes”, do you think that simply bubbling O2 into these waters would work? Justify your answer.Please anwser the following it’s just naming structures. Thank u so much ??help pls is this answer corrcet, i cant stack li+ and cu- on top of each other ?
- The bonds are stronger in either the TiCl4(g) or the CCl4(g)? What is your reasoning?I'm trying to determine if this compound is ionic or covalent, but I'm pretty clueless. I would be greatly appreciative of any help! The compound is Crocin, found in Saffron.Tu Re-order each list in the table below, if necessary, so that the atoms or lons in it are listed in order of decreasing size. Please don't provide the handwriting solution
- Using Table 8.3, estimate ΔH for each of the followinggas-phase reactions (note that lone pairs on atoms are notshown):Group A: solution conductivity (MS) NaCl 6594 CaCl2 13188 AlCl3 16311 Group B: solution conductivity (MS) HCl 21809 Hc2H3O2 639 H3PO4 8805 For H3PO4, does the subscript "3" of hydrogen in this formula seem to result in additional ions insolution as it did for AlCl3in Group A? Explain.Draw an octet-rule Lewis structure for POCl3: Total count of valence e¯’s: a) in the formula = __ b) as dots and dashes in your O.R.-Lewis structure = _____ Bond orders: P–O _______ P–Cl _______ (like triple in N2, single in H2O …) Count e¯-groups around P: _____ --> e¯-group shape around P is ________________ Molecular shape is _______________ The molecule is ? not polar (mark one) Oxidation numbers: O ____ Cl ____ P ____