5.What is the benefit of random selecting single sample from a population
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- Consider the following information about travelers onvacation (based partly on a recent Travelocity poll):40% check work email, 30% use a cell phone to stayconnected to work, 25% bring a laptop with them, 23%both check work email and use a cell phone to stayconnected, and 51% neither check work email nor usea cell phone to stay connected nor bring a laptop. Inaddition, 88 out of every 100 who bring a laptop alsocheck work email, and 70 out of every 100 who use acell phone to stay connected also bring a laptop.a. What is the probability that a randomly selectedtraveler who checks work email also uses a cellphone to stay connected?b. What is the probability that someone who brings alaptop on vacation also uses a cell phone to stayconnected?c. If the randomly selected traveler checked work emailand brought a laptop, what is the probability that he/she uses a cell phone to stay connected?A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.9 4.2 4.1 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.9 4.1 4.5 5.1 3.3 4.8 3.5 2.4 3.1 3.5 5.2 What is the value of the sample test statistic? (Test the difference ?1 − ?2. Round your answer to three decimal places..)A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.9 4.1 4.5 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference ?1 − ?2. Round the test statistic and critical value to three decimal places.) test statistic critical value
- A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.5 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.9 4.1 4.5 5.1 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. (a) Use a calculator to calculate x1, s1, x2, and s2. (Round your answers to four decimal places.) x1=s1=x2=s2= (b) Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. (i) What is the level of significance? State the null and alternate hypotheses. H0: ?1 = ?2; H1: ?1 ≠ ?2H0: ?1 = ?2; H1: ?1 > ?2 H0: ?1 < ?2; H1: ?1 = ?2H0: ?1 = ?2; H1: ?1 < ?2 (ii) What sampling distribution will you use? What…A random sample of n1 = 10 regions in New England gave the following violent crime rates (per million population). x1: New England Crime Rate 3.3 3.7 4.2 3.9 3.3 4.1 1.8 4.8 2.9 3.1 Another random sample of n2 = 12 regions in the Rocky Mountain states gave the following violent crime rates (per million population). x2: Rocky Mountain Crime Rate 3.5 4.1 4.7 5.5 3.3 4.8 3.5 2.4 3.1 3.5 5.2 2.8 Assume that the crime rate distribution is approximately normal in both regions. Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than in New England? Use ? = 0.01. Solve the problem using both the traditional method and the P-value method. (Test the difference ?1 − ?2. Round the test statistic and critical value to three decimal places.) test statistic critical value Find (or estimate) the P-value. A. P-value > 0.250 B. 0.125 < P-value < 0.250 C. 0.050 < P-value < 0.125 D. 0.025 < P-value <…