57. [Algorithmic] Sulfamic acid, HSO,NH, (molar mass = monoprotic acid that can be used to standardize a strong base: 97.1 g/mol), is a strong HSO,NH,(aq) + KOH(aq) → KSO,NH,(aq) + H,O(1) A 0.179-g sample of HSO,NH, required 19.4 mL of an aqueous solution of KOH fo complete reaction. What is the molarity of the KOH solution? a) 9.25 M b) 9.50 x 10-5 M c) 0.0950 M d) 0.194 M e) none of these

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Chapter13: Acids And Bases
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Problem 102QAP: You are asked to determine whether an unknown white solid is acidic or basic. You also need to say...
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Answer these questions.
d) 151 g/mol
e) 82.7 g/mol
ANS: a)
SECTION: 4.8
LEVEL: mediu
57. IAlgoríthmic] Sulfamic acid, HSO,NH, (molar mass = 97.1 g/mol), is a strong
monoprotic acid that can be used to standardize a strong base:
HSO,NH,(aq) + KOH(aq) → KSO,NH,(aq) + H,O(1)
A 0.179-g sample of HSO,NH, required 19.4 mL of an aqueous solution of KOH for
complete reaction. What is the molarity of the KOH solution?
a) 9.25 M
b) 9.50 x 10-5 M
c) 0.0950 M
d) 0.194 M
e) none of these
ANS: c)
SECTION: 4.8
LEVEL: medium
Transcribed Image Text:d) 151 g/mol e) 82.7 g/mol ANS: a) SECTION: 4.8 LEVEL: mediu 57. IAlgoríthmic] Sulfamic acid, HSO,NH, (molar mass = 97.1 g/mol), is a strong monoprotic acid that can be used to standardize a strong base: HSO,NH,(aq) + KOH(aq) → KSO,NH,(aq) + H,O(1) A 0.179-g sample of HSO,NH, required 19.4 mL of an aqueous solution of KOH for complete reaction. What is the molarity of the KOH solution? a) 9.25 M b) 9.50 x 10-5 M c) 0.0950 M d) 0.194 M e) none of these ANS: c) SECTION: 4.8 LEVEL: medium
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