6. Given the following chromatogram, calculate the Rf values of A and B.Solvent front (Assume 12.2 cm)12 cmA10 cmA =8 cm6 cmB4 cmB =2 cm0 cmBaseline (0 cm)distance traveled by the soluleRfdistance trareed by the sowentfront131

As per the given figure the distance travelled by A is around 11 cm and the distance travelled by B…

Answered: 6. Given the following chromatogram,…

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter2: Resolution Of Matter Into Pure Substances, I.paper Chromatography

Section: Chapter Questions

Problem 1ASA

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The following Rf values were computed from a normal phase chromatography experiment. Arrange them from most polar to least polar. I - 0.25 II - 0.84 III - 0.56 IV- 0.67 Group of answer choices II > IV > III > I I > III > IV > II I > II > III > IV IV > II > III > I
Table 1: Chromatography Results Mobile Phase: Distilled Water Solvent front distance (cm): 8 cm M&M Candy Separated Spot Color Migration Distance (cm) (distance to center of spot from origin) Red M&M Red 7.5 cm Green M&M Yellow 5.3 cm Blue 7.7 cm Blue M&M Blue 7.8 cm -please help with this part Calculations/Results: Table 1: Results with Distilled Water M&M Candy Separated Spot Color Rf Value Red M&M Green M&M Blue M&M Rf = Distance traveled by component in a given time/ Distance traveled by solvent in same time Show work with units for one sample calculation.
In a chromatographic separation of two components A and B. Component A has a higher Rf value than component B. This implies that: A. Component B has a higher affinity than A for the mobile phaseB. component B elutes first in the columnC. A has a higher affinity than B for the mobile phaseD. Component A has a higher affinity than B for the stationary phase.
Based on the chromatograms, Symmetry C18 (top) is less selective than Symmetry Shield RP18 (bottom) for the analytes given, true or false?
Describe with illustrations the observed peak for a chromatogram with the following tailing factors (TF): a. TF = 1b. TF > 1c. TF < 1
The following Rf values were computed from a normal phase chromatography experiment. Arrange them from most polar to least polar. I - 0.25 II - 0.84 III - 0.56 IV- 0.67
Explain the following (1) Column Chromatography(CC) (2) Paper Chromatography (3) Thin Layer Chromatography(TLC) (4) Gas Chromatography (GC)
Paper Chromatography Calculate the Rf for a spot that travels 2.41 cm from the baseline while the solvent travels 7.85 cm from the baseline. Answer with the number; there are no units for Rf I got the answer: 0.3070063694267516 2.41/7.85 = 0.3070063694267516 just wanted to make sure.
The Kb for methylamine (CH3NH2) at 25 ∘C is 4.4×10−4. What is the value of ΔG when [H+] = 6.8×10−9 M, [CH3NH+3] = 2.3×10−3 M, and [CH3NH2] = 9.20×10−2 M?
Mass spectrometry is an extremely versatile detection system for GC. However, interfacing an HPLC system to a mass spectrometer is a much more difficult task. Describe the major reasons why it is more difficult to combine HPLC with mass spectrometry than it is to combine GC with mass spectrometry.
All types of chromatography depend on partitioning a sample between a stationary phase and a mobile phase. Identify the stationary phase and mobile phase for each of the following types of chromatography. -TLC -GC
Using thin-layer chromatography showed that the black dye used in a brand of writing ink contained blue, red, orange and yellow components. The Rf values of these substances using ethanol as the solvent are 0.59, 0.32, 0.80 and 0.19, respectively. How far apart would the blue and yellow components be after the solvent front had moved 8.0 cm from the origin?

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6. Given the following chromatogram, calculate the Rf values of A and B. Solvent front (Assume 12.2 cm) 12 cm A 10 cm A = 8 cm 6 cm B 4 cm B = 2 cm 0 cm Baseline (0 cm) distance traveled by the solule Rf distance trareed by the sowent front 131