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- Adol Condensation Lab, Organic Chemistry 2: The same physical property that helps drive the reaction to completion can also stall out the reaction before it starts. What do we do in the procedure that helps minimize this concern? (initially I said that the driving force is 1) reactivity of carbonyl compounds 2) stability of the product please be as detailed as possible, will mark as helpfulAssume that 2-chloropropane reacts with CN− in an SN2 reaction. Use the JSME editor () to draw the structure of the substitution product of the reaction. The guide on how to draw your structure can be found here Important Note: When drawing the structures in the JME editor please adhere to the following formats: 1. If the nucleophile is OH−, DO NOT manually add the "H" to the final product 2. If the nucleophile is CN−, be sure to include the appropriate bonding between the C and N in the final productRearrangements can occur during the dehydration of 1° alcohols even though no 1° carbocation is formed—that is, a 1,2-shift occurs as the C— OH2+ bond is broken, forming a more stable 2° or 3° carbocation, as shown in Equation [1]. Using this information, draw a stepwise mechanism for the reaction shown in Equation [2]. We will see another example of this type of rearrangement in Section 16.5C.
- For question 1c below, which of the puzzle pieces makes the best sequence for each synthesis? You must solve the syntheses with the puzzle pieces provide and nothing else. One piece can only be used once.Monensin (1) is a potent antibiotic. JACS 1980, 102, 2118-2120. 1. Use arrows provided a pathway from (1) to (2) when we add a mild base sodium bicarbonate followed by iodine (I2). 2. What was a similar reaction between Br2 and an alkene? What did we name the intermediate?- For the dehydration shown, use curved arrows to show the formation of the carbocation intermediate in the presence of sulfuric acid H2SO4H2SO4, then draw the structures of the minor and major products of the elimination. Picture: Cyclohexane (no double or triple bonds) with a methyl group and an alcohol group (HO 4e- on O) on C1 (bottom) reacting with H2SO4 -> "Major and Minor Products" -The H2SO4H2SO4 is abbreviated as H+H+ in the drawing module. Do not delete any pre‑drawn bonds, charges, or lone pairs. If you accidentally make a mistake, remove the last change by using the undo button on the lower left or revert the drawing palette to the original state by selecting the More menu, then select Reset Drawing. Step 1: Use curved arrows to complete the protonation mechanism of the alcohol. Step 2: Use a curved arrow to show the formation of the carbocation intermediate for the elimination. (Picture 1) -Step 3: This tertiary carbocation intermediate readily undergoes…
- what is the difference between these two the aldo condensation reaction was preformed Part A NaoH= 2.5g = 0.0625 mol Benzaldehyde= 2.65 g =0.0250 mol Acetone 0.725 g = 0.0125 mol Theoretical yield=0.0125 mol Actual yield= 2.1g Percent yield=71.67% Expected melting point= 110.5-112 degree Celsius Melting point observered= 112 degree Celsius Part B acetophenone 0.5 g, 4.2 mmol Para-methylbenzaldehyde 0.5 g, 4.2 mmol NaOH=0.18g = mol Theroretical yield=0.93g =0.0519 mol Percent yield=76.8% Actual yield= 0.715 g Melting point observered= 93 degree Celsius Expected melting point =93-94.5 degree CelsiusFill in the fields (reagent or products) left blank in the reaction below.Why is the mechanism shown in Figure 28 not plausible? * A- The reagent does not have a good leaving group. B- Water is too weak a base for the reaction to occur. C- The structure of the haloalkane prevents the nucleophile from coming close to the alpha carbon atom. D- None of these statements are correct. E- All these statements are correct.
- Please choose which product would result from the reaction.True or False?: Using Cl2/hν in place of Br2/hν on the same compound seen above would yield only one product.Help ASAP Illustrate the resonance effect of the methoxy group -OCH3, on the structure of the benzene ring. Do this by writing all the possible resonance forms for methoxybenzene, including the hybrid. Based on your structures, explain how the presence of the -OCH3 group affects: (i) the reactivity of the benzene ring towards electrophilic attack; (ii) the orientation or point of attack of an incoming electrophilic reagent on the benzene ring.help me please Please fill in the reagents,intermediates, and/or products of the following reactions. all the reactions shall be covered in Chapter 12-15 from Organic Chemistry, 6th Edition by Marc Loudon and Jim Parise.
