7). Translate a recursive version of the function BitCount into RISC-V assembly code. This function counts the number of bits that are set to 1 in an integer. The parameterX is passed to your function in register x10. Your function should place the return value in register x1. Use the calling convention of RISC-V to save and restore the required registers and variables.

7). Translate a recursive version of the function BitCount into RISC-V assembly code. This function counts the number of bits that are set to 1 in an integer. The parameterX is passed to your function in register x10. Your function should place the return value in register x1. Use the calling convention of RISC-V to save and restore the required registers and variables.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Floating-point is defined as follows:
Java Program A Number is said to be a PRIME number if it only have 2 factors which is 1 and itself. The number 1 is neither a PRIME or COMPOSITE number. Input: 3 Output: Input Number: 3I am Optimus Prime
code in java pls Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers represent color by combining the sub-colors red, green, and blue (rgb). Each sub-color's value can range from 0 to 255. Thus (255, 0, 0) is bright red, (130, 0, 130) is a medium purple, (0, 0, 0) is black, (255, 255, 255) is white, and (40, 40, 40) is a dark gray. (130, 50, 130) is a faded purple, due to the (50, 50, 50) gray part. (In other words, equal amounts of red, green, blue yield gray). Given values for red, green, and blue, remove the gray part. Ex: If the input is: 130 50 130 the output is: 80 0 80 Find the smallest value, and then subtract it from all three values, thus removing the gray.
Assignment for Computer Architecture You are to write a program in MIPS that computes N! using recursion. Remember N! is the product of all the numbers from 1 to N inclusive, that is 1 x 2 x 3 x (N – 1) x N. It is defined as 1 for N = 0 and is undefined for values less than 0. The programs first requests the user to input the value of N (display a prompt first so the user knows what to do). If the input value is less than 0, the program is to display “N! undefined for values less than 0” and then requests the user to input the value of N again. If the value input is non-negative, it is to compute N! using a recursive function, that is one that calls itself. You are to have your name, the assignment number, and a brief description of the program in comments at the top of your program. Since this is an assembly language program, I expect to see comments on almost every line of code in the program. Also make the code neat: line up the command fields, the register fields, and the comment…
Java Code / JAVA Programming Write a block of code that generates a random int 'r' between 0 and 10, then uses that number to calculate the area of a circle with radius 'r'.
Example: Enter an integer = 75 Smallest divisor is = 3
Convert the following java code to C++ //LabProgram.javaimport java.util.Scanner;public class LabProgram {public static void main(String[] args) {//defining a Scanner to read input from the userScanner input = new Scanner(System.in);//reading the value for Nint N = input.nextInt();//creating a 1xN matrixint[] m1 = new int[N];//creating an NxN matrixint[][] m2 = new int[N][N];//creating a 1xN matrix to store the resultint[] result = new int[N];//looping and reading N integers into m1for (int i = 0; i < N; i++) {m1[i] = input.nextInt();}//looping from 0 to N-1for (int i = 0; i < N; i++) {//looping from 0 to N-1for (int j = 0; j < N; j++) {//reading an integer and storing it into m2 at position i,jm2[i][j] = input.nextInt();}}//multiply m1 and m2, store result in result//looping from 0 to N-1for (int i = 0; i < N; i++) {//looping from 0 to N-1for (int j = 0; j < N; j++) {//multiplying value at index j in m1 with value at j,i in m2, adding to current value at index i// on…
Write a multiplication program using Java. Ask user to solve problems with random numbers from 1-20. The program stops after an incorrect answer. The output should look like: 14 * 8 = 112 Correct! 5 * 12 = 60 Correct! 8 * 3 = 24 19 * 14 = 256 Incorrect; the answer was 266 You solved 2 correctly
What is output (printed) by the program (pseudocode) shown below. Assumingpass-by-reference __________: int c; // globalprocedure TTT(int x){ x = x+2; c = c-1;}main(){ c = 18; TTT(c); Print(c)} A)20 B)18 C)17 D)19
Problem solving using recursion First code i solve it this is the second part // define a scanner attached to keyboard available to all functions final static Scanner cin = new Scanner(System.in); /** * @param args the command line arguments */ public static void main(String[] args) { // TODO code application logic here out.print("CPS 151 ICA 04 String matching by YOUR NAME\n\n"); out.print("Enter the text (one word): "); String hayStack = cin.next(); out.print("Enter the pattern (one word): "); String needle = cin.next(); if (find(needle, hayStack)) out.println(needle + " was found in " + hayStack); else out.println(needle + " was not found in " + hayStack); } // end main private static boolean find(String needle, String hayStack) { int patLen = needle.length(); int textLen = hayStack.length(); // base case 1 if (patLen > textLen) { // failure } else if (needle.startsWith(needle)) { // base case 2 MODIFY!! // SUCCESS } else { // recurse } return false; // dummy to keep NetBeans…
change to ada language import java.util.scanner; public class problem41 { public static void main(string[] args) { scanner input = new scanner(system.in); int positives = 0; // count the number of positive numbers int negatives = 0; // count the number of negative numbers int count = 0; // count all numbers double total = 0; // accumulate a totol // promopt the user to enter an integer or 0 to exit system.out.print("enter an integer, the input ends if it is 0: "); int number = input.nextint(); if (number == 0) { // test for sentinel value system.out.println("no numbers are entered except 0"); system.exit(1); } while (number != 0) {// test for sentinel value if (number > 0) { positives++; // increase positives } else { negatives++; // increase negatives } total += number; // accumulate total count++; // increase the count number = input.nextint();//read the next number } // calculate the average double average = total / count; // display results system.out.println( "the number of…
In C++, How many positive values could an unsigned int hold on a computer where an integer is made up of 4 bits.