9. For the following aspartate reaction in the presence of inhibitor, Km = 0.00065 M. Determine Vmax in both reactions and in the reaction without inhibitor, the Km. Identify whether the inhibition is competitive, non-competitive or uncompetitive.
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- The enzyme β-methylaspartase catalyzes the deamination of β-methylaspartate. For this aspartate reaction in the presence of the inhibitor hydroxymethylaspartate (3.8 M), determine KM and whether the inhibition is competitive or noncompetitive (KI = 1.0 M). [S], M V w/o inhibitor, M/s V w/ inhibitor, M/s 1x10-4 0.0259 0.0098 5x10-4 0.0917 0.040 1.5x10-3 0.136 0.086 2.5x10-3 0.150 0.120 5x10-3 0.165 0.142 In the ABSENCE of inhibitor: The Lineweaver-Burke equation is 1V=1V= __________ (1[S])(1[S]) + __________, and the KM is __________ M. In the PRESENCE of inhibitor: The Lineweaver-Burke equation is 1V=1V= ____________ (1[S])(1[S]) + ___________, and the KM is ___________ M. The type of inhibition is ____________. Round-off all answers to two (2) significant figures.For the following aspartate reaction in the presence of inhibitor, Km = 0.00065 M. Determine Vmax in both reactions and in the reaction without inhibitor, the Km. Identify whether the inhibition is competitive, non-competitive or uncompetitive. ( see attached picture ) how I and S bind to the E as shown by the Lineweaver Burk plot. the significance of the following obtained values for Km and Vmax. effect in slope and x-interceptThe enzyme β-methylaspartase catalyzes the deamination of β-methylaspartate. For this aspartate reaction in the presence of the inhibitor hydroxymethylaspartate (3.8 M), determine KM and whether the inhibition is competitive or noncompetitive (KI = 1.0 M). In the ABSENCE of inhibitor: The Lineweaver-Burke equation is 1V=1V= __________ (1[S])(1[S]) + __________, and the KM is __________ M. In the PRESENCE of inhibitor: The Lineweaver-Burke equation is 1V=1V= ____________ (1[S])(1[S]) + ___________, and the KM is ___________ M. The type of inhibition is ____________. Round-off all answers to two (2) significant figures.
- Calculate KI' of the inhibitor from the information given. All information may not be needed to calculate. K'm = (29Ki+1.45x10^-10)/Ki Vmax = 11.7 µMs-1 Kcat = 130 s^-1 Vo = 3.0 μMs-1 S = 10 μM Et = 0.09 µM Inhibitor Concentration = 5x10^-12A new drug, Proinebrium, that reduces Kcat (Ki = 2.0 uM) has been developed to treat ethylene glycol poisoning. (1) What concentration of Proinebrium is required to achieve 50% inhibition of ethylene glycol metabolism by alcohol dehydrogenase when the concentraion of ethlyene glycol in the blood is 50 uM?While furthering your studies of iocane powder you determine that a ceular enzyme, iocase will degrade it. Under normal conditions, iocase shows km 0f 1.85 uM and a kcat of 76. The drug sildenafil was found to have no effect on the km of iocanse yet the kcat was found to drop 58 minutes^-1, when the drug was added and no other changes were made in the reaction conditions. What can be inferred from this data? (remember kcat = vmax/et) Sildenafil acts as an uncompetitive inhibitor of iocanse Sildenafil acts as a noncompetitive inhibitor of iocanse The effect of sildenafil could be countered by adding more iocane to the reaction The y-intercept of the sildenafil inhibited iocanse would appear to be lower on a Lineweaver burke plot as compared to uninhibited iocanase The slope of a Lineweaver burke plot of the inhibited versus uninhibited iocanase would remain unchanged
- The enzyme serine hydroxymethy ltransferase (SHMT) catalyses the conversion of serine into glycine. The fo llowing table gives the initial rates, vo, for the SHMT-catalysed reaction of the substrate serine at var ious concentratio ns of serine, lSI.[S]/(mmol dm-3) 10 20 30 40vo(μmol dm-3 s-1) 1.63 2.94 4.10 4.95Use the data to determine the values of the MichaelisMenten constant, the maximum velocity of the reaction, and the maximum turnover number of the enzyme.An experiment was carried out to measure the reaction rate of hydrolysis of acetylcholme (substrate) with serum enzymes (Eadie, 1949). In the experiment, two experiments were conducted, namely experiment 1 without using a prostigmine inhibitor and experiment 2 using a prostigmine inhibitor at 1.5 x 10^-7 mol/l. the data obtained are: a. Is prostigmine competitive or noncompetitive inhibitor? b. determine the value of km and rmax for the two experiments, compareWhich of the following is true about a mixed type inhibition? a. None of these is true b. A Lineweaver-Burk plot will give parallel lines c. The lines of a Lineweaver-Burk graph will cross in the top left quadrant d. The KM will change but not the Vmax
- The inhibitory effect of an uncompetitive inhibitor is greater at high [S] thanat low [S]. Explain this observation.A particular enzyme-catalyzed reaction has an apparent Vmax = 9.00 nmol s-1 and α' = 3.00 when 2.00 µmol L-1 inhibitor X is present and uncompetitively inhibiting the reaction. Calculate Vmax for the uninhibited reaction in nmol s-1.What are the measures to inhibit the Maillard reaction in undesirable situations. please explain detailed