9. L0phtCrack is formerly known as LC3. a) True b) False
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Control structures
Control structures are block of statements that analyze the value of variables and determine the flow of execution based on those values. When a program is running, the CPU executes the code line by line. After sometime, the program reaches the point where it has to make a decision on whether it has to go to another part of the code or repeat execution of certain part of the code. These results affect the flow of the program's code and these are called control structures.
Switch Statement
The switch statement is a key feature that is used by the programmers a lot in the world of programming and coding, as well as in information technology in general. The switch statement is a selection control mechanism that allows the variable value to change the order of the individual statements in the software execution via search.
9. L0phtCrack is formerly known as LC3.
a) True
b) False
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- 19.16 LAB: Area of a triangle Using Heron's formula, you can calculate the area of a triangle if you know the lengths of all three sides. Given the length of each side of a triangle as input, calculate the area of the triangle using Heron's formula as follows: s = half of the triangle's perimeter area = the square root of s*(s-a)*(s-b)*(s-c), where a, b, and c are each sides of the triangle. Hint: Use the math function sqrt() for calculating the square root. Output the floating-point value of the area with two digits after the decimal point using the following statement once before all other cout statements:cout << fixed << setprecision(2); Ex: If the input for a, b, and c is: 3.0 4.0 5.0 the output is: Triangle area = 6.00 #include <iostream>#include <iomanip>#include <cmath>using namespace std; int main() { /* Type your code here. */ return 0;3. Intermediate CodeThe following statement is known:A = - A * (A + B ) - (B – C) / DPlrase make: c. Triples1(a) Create an eight-digit binary number containing a point. This eight-digit binary number must contain at least four l's with two digits after the point. Convert to denary.
- 7. the following program displays #include <iostream> using namespace std; int main(){ cout<<"4+5+6" <<endl; return 0;} A. 15 B. 456 C.4 5 6 D.4+5+6#include "stdafx.h"#include<iostream>#include<string>#include <iomanip> in c++ How do I list all of the price entered. for example, if the customer says yes three times. How do I list all three? below is an example const float discount = .80;double cost;double Price;char ans; do{cout << "\n\nPlease enter the cost to replace your building: ";cin >> cost;price = cost * discount;//calculate the insurance cout << "Hello, " << name << " The price is << fixed << setprecision(2) << price << endl;cout << "\nWould you like to input another? (Y/N): ";//prompts user to enter another insurancecin >> answ;} while (answ == 'Y' || answ == 'y');change normal body temperature to 36.5–37.5 °C #include<iostream>using namespace std;int main(){ float temp;cout<<"Enter the body temperature in Celsius\n";cin>>temp;if (temp>=37){cout<<"The quarantine of the patient is required\n";cout<<"Enter the name of the patient\n";string patient;cin>>patient;cout<<"Where the passenger is from\n";string place;cin>>place;cout<<patient<<" from "<<place<<"is to be quarantined at Hospital"; }cout<<"Normal temperature\n";}
- 4.7 for repetition #include <iostream>#include <iomanip>using namespace std;int main(){long USD, maxUSD; // Amount in USDdouble rate; // Exchange rate USD <-> MYRcout << "\n* * * * TABLE OF EXCHANGE * * * *\n ";cout << "* United State Dollar (USD) to Malaysia Ringgit (MYR) *\n\n";cout << "\nPlease give the rate of exchange: ";cout <<" \n\n 1 USD in RM MYR: ";cin >> rate;cout << "\n Please enter the USD you want to change: ";cin >> maxUSD;// Outputs the table & Titles of columns:cout << "\n If Rate Now is : " << rate << endl;cout << "\n so, USD to RM exchange is : "<< endl;cout << '\n'<< setw(12) << "USD" << setw(20) << "MYR";cout << '\n'<< setw(16) << "---------------------------------------------" ;cout << '\n'<< setw(24) << " >>> " ;// Formatting RM-MYR:cout << setprecision(2) << endl;long lower, upper,…194. ‘set args ‘ without arguments can ___________ a. initialize all the arguments b. remove all the arguments c. no change d. show all the argumentsPlease help to answer the min Here is the code #include using namespace std; int main() { int numbers[10]; int i; for (i=0;i>numbers[i]; int numbers2[10],j,k; for(i=0;ic) { max1=rep; c=top; } } cout<
- C++ Fix this code so that it displays in the format like the image shown where the principal and rate should have a fixed precision of 2 for each of the five percentages 5%,6%,7%,8%,9%,10%. The amount of the deposit should not have the fixed precision and should remain in the decimal format. #include <iostream>#include <iomanip>#include <cmath>using namespace std; int main(){double principal{ 1000 };double rate{ 0.05 }; for (rate; rate <= 0.10; rate += 0.01) {cout << "" << endl;cout << "Initial principal: " << principal << endl;cout << "Interest Rate: " << rate * 100 << "%" << endl;cout << setw(4) << "Year" << setw(20) << "Amount on deposit" << endl;for (unsigned int year{ 1 }; year <= 10; year++) {double amount = principal * pow(1.0 + rate, year); cout << setw(4) << year << setw(20) << amount << endl; }}}Need help correcting the 24-hour clock as its showing as regular time! #include <iostream>#include <ctime>#pragma warning(disable : 4996) using namespace std; time_t now = time(0);tm* local = localtime(&now); int hour = local->tm_hour;int minutes = local->tm_min;int sec = local->tm_sec; // Function to display the 12-hour clockvoid Clock12() { // Converts 24-hour clock to 12-hour if (hour > 12) { hour -= 12; } cout << "*****************************" << " " << "*****************************\n"; cout << "* 12-Hour Clock *" << " " << "* 24-Hour Clock *\n"; cout << "* " << (hour < 10 ? "0" : "") << hour << ":" << (minutes < 10 ? "0" : "") << minutes << ":" << (sec < 10 ? "0" : "") << sec << (local->tm_hour < 12 ? " AM" : " PM") << " * ";} // Function to display the 24-hour…In C please 20.4 LAB: Leap year - functions A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is: 1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year. Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise.bool IsLeapYear (int userYear) Note: This is a lab from a previous chapter that now…