9. Water gas is a 1:1 mole ratio of CO (g) and H, (g). It is burned in air: 2CO(g) + O,(g) 2CO,(g) A,H =-566 kJ mol > %3D 2H,(g) + O2(g) - → 2H,0(1) A,H =-571.7 kJ mol (1) Find the number of moles of CO (g) and H, (g) present in 50.0 g of water gas. (Remember that they are present in a 1: 1 mole ratio). (2) Use the preceding thermochemical equations to find the enthalpy change when 50.0 g of water gas are burned in air.
9. Water gas is a 1:1 mole ratio of CO (g) and H, (g). It is burned in air: 2CO(g) + O,(g) 2CO,(g) A,H =-566 kJ mol > %3D 2H,(g) + O2(g) - → 2H,0(1) A,H =-571.7 kJ mol (1) Find the number of moles of CO (g) and H, (g) present in 50.0 g of water gas. (Remember that they are present in a 1: 1 mole ratio). (2) Use the preceding thermochemical equations to find the enthalpy change when 50.0 g of water gas are burned in air.
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.132QP
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