949.19cm-1. 93,52%T 1058.50cm-1. 92.92T 95 140.28cm-1. 8 90 6.29cm-1, 86.86T 85 80 1766.15cm-1, 78.2%T 9141cm-1, 77.64 544.60cm-1, 78.51%T 75 1508.16cm-1, 73.74%T 785.97cm1, 72.96%T 70 1257.45cm-1, 65. 45%T 65 11132cm-1, 63.9%T 60 806.71cm-1, 61.47%T 1198.16cm-1, 58.75%T 1016.11cm-1, 59.27%T 55 53 4000 3000 1750 cm-1 3500 2500 2000 1500 1250 1000 750 500450 Name Description - Expt 11 Base Product Sample 214 By organico Date Friday, March 20 2020

949.19cm-1. 93,52%T 1058.50cm-1. 92.92T 95 140.28cm-1. 8 90 6.29cm-1, 86.86T 85 80 1766.15cm-1, 78.2%T 9141cm-1, 77.64 544.60cm-1, 78.51%T 75 1508.16cm-1, 73.74%T 785.97cm1, 72.96%T 70 1257.45cm-1, 65. 45%T 65 11132cm-1, 63.9%T 60 806.71cm-1, 61.47%T 1198.16cm-1, 58.75%T 1016.11cm-1, 59.27%T 55 53 4000 3000 1750 cm-1 3500 2500 2000 1500 1250 1000 750 500450 Name Description - Expt 11 Base Product Sample 214 By organico Date Friday, March 20 2020

Chemistry & Chemical Reactivity

9th Edition

ISBN:9781133949640

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

ChapterL: Let's Review

SectionL.3: Mathematics Of Chemistry

Problem 4RC

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Kerosene has a specific weight of γ_k = 51.1 lb/ft³ and benzene has a specific weight of γ_b = 56.2 lb/ft³. Determine the amount of kerosene that should be mixed with 8 lb of benzene so that the combined mixture has a specific weight of γ = 52.0 lb/ft³
1. The formula for lactose is C12H22O11, and the monohydrate is C12H22O11*H2O. What is the percent by weight of lactose in lactose monohydrate? Give your answer to four significant digits as a percentage (xx.xx) - do not include "%" 2. If the image in the polarimeter appears as shown above, which button should you press? The "up" or R blue button The red button The green button No button, you have found the correct optical rotation. The "down" or L blue button 3. Suppose you measure 7.000 g of a substance and dissolve it in 100.0 mL of water, and place the sample in a 2.000 dm path-length sample tube, and then observe a rotation of 19.5 degrees with the sodium-D lamp. What is the specific rotation? Give your answer to three digits, without units (xxx)
P = P2O5 × 0.44 P2O5 = P × 2.29 K = K2O × 0.83 K2O = K × 1.21 1 tonne = 1,000 kg 1 ha = 10,000 m2 Using the conversions above calculate : 1.How much N and K are in a 25 kg bag of 12-22-18? 2. How much P2O5 and P are in a 20 kg bag of 0-46-0? 3. How much K2O and P2O5 are in a 35 kg bag of 12-22-18?
I asked this question earlier but I think I forgot to include a conversion wht we know : mm of citrix acid = 192.14g/moldensity of citrix acid =166g/cm3 1 lime = 2tbsp of juice = 6 tsp 1tsp = 4.929x10-3L Q: assume citrix acid makes up 7.96% by volume of the lime juice . How many moles of citrix acid are in the recipe ( calls for 1 lime juice)
P = P2O5 × 0.44 P2O5 = P × 2.29 K = K2O × 0.83 K2O = K × 1.21 1 tonne = 1,000 kg 1 ha = 10,000 m2 Using the conversions above calculate : How much N, P and K are in a 15 kg bag of 0-46-0? How much N and P2O5 are in half tonne of DAP (18-46-0)? How much P and N are in quarter tonne of DAP (18-46-0)?
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